• 推箱子 复杂版(多个箱子)


    多个箱子:

    namespace ConsoleApplication1
    {
        class Program
        {
            private static void ditu(int[, ,] dt, int i)
            {
                for (int j = 0; j < 10; j++)
                {
                    for (int k = 0; k < 10; k++)
                    {
                        if (dt[i, j, k] == 0)
                        {
                            Console.Write("  ");
                        }
                        else if (dt[i, j, k] == 1)
                        {
                            Console.Write("");
                        }
                        else if (dt[i, j, k] == 2)
                        {
                            Console.Write("");
                        }
                        else if (dt[i, j, k] == 3)
                        {
                            Console.Write("");
                        }
                        else if (dt[i, j, k] == 4)
                        {
                            Console.Write("");
                        }
                    }
                    Console.Write("
    ");
                }
            }
            static void Main(string[] args)
            {
                 int x = 1, y = 1, i = 0;
                int[, ,] dt = new int[3, 10, 10]  //定义一个二维数组用于接收地图
                    {
                       { 
                         {1,1,1,1,1,1,1,1,1,1},
                         {1,4,0,1,0,0,0,0,0,1},
                         {1,0,0,0,0,0,2,0,3,1},
                         {1,0,1,1,0,1,0,0,0,1},
                         {1,0,0,0,0,0,0,0,0,1},
                         {1,3,1,1,1,1,1,2,1,1},
                         {1,2,1,0,0,0,0,0,0,1},
                         {1,0,0,0,0,1,1,0,0,1},
                         {1,1,0,1,0,0,0,3,0,1},
                         {1,1,1,1,1,1,1,1,1,1},
                       },
                       { 
                         {1,1,1,1,1,1,1,1,1,1},
                         {1,1,1,1,4,0,1,0,3,1},
                         {1,1,1,3,0,0,2,0,0,1},
                         {1,1,0,0,2,0,1,0,0,1},
                         {1,0,0,0,1,1,1,0,0,1},
                         {1,0,1,1,0,0,0,0,0,1},
                         {1,0,0,0,0,2,0,0,1,1},
                         {1,0,3,0,0,0,1,1,1,1},
                         {1,0,0,0,0,1,1,1,1,1},
                         {1,1,1,1,1,1,1,1,1,1},
                       },
                       { 
                          {1,1,1,1,1,1,1,1,1,1},
                          {1,1,0,0,4,0,0,3,1,1},
                          {1,1,0,2,0,0,0,2,3,1},
                          {1,1,0,0,2,1,1,0,0,1},
                          {1,1,0,1,0,0,0,3,0,1},
                          {1,0,3,0,0,0,1,0,1,1},
                          {1,0,0,1,1,2,0,0,1,1},
                          {1,3,2,0,0,0,2,0,1,1},
                          {1,1,3,0,0,0,0,0,1,1},
                          {1,1,1,1,1,1,1,1,1,1},
    
                      } 
                    };
                try
                {
                    int count = 0;//临时变量
                    int xzs = 0;//箱子数
                    for (int j = 0; j < 10; j++)
                    {
                        for (int k = 0; k < 10; k++)
                        {
                            if (dt[i, j, k] == 3)
                            {
                                xzs++;
                            }
                        }
                    }
                    while (true)
                    {
                        int temp = 0;
                        ConsoleKeyInfo s = Console.ReadKey();  //s用于接收用户输入的键
                        if (s.Key.ToString() == "DownArrow")
                        {
                            if (dt[i, x + 1, y]!=1)
                            {
                                
                           
                            if (dt[i, x + 1, y] == 0)//如果小人的下一步是0(空格),则两个元素交换  (下同)
                            {
                                temp = dt[i, x, y];
                                dt[i, x, y] = dt[i, x + 1, y];
                                dt[i, x + 1, y] = temp;
                                x++;
                            }
                            else if (dt[i, x + 1, y] == 2 && dt[i, x + 2, y] == 0)//如果小人的下一步是箱子,箱子的下一步是空格,则三个元素进行交换 (下同)
                            {
                                temp = dt[i, x + 2, y];
                                dt[i, x + 2, y] = dt[i, x + 1, y];
                                dt[i, x + 1, y] = temp;
                                temp = dt[i, x + 1, y];
                                dt[i, x + 1, y] = dt[i, x, y];
                                dt[i, x, y] = temp;
                                x++;
                            }
                            else if (dt[i, x + 2, y] == 3 && dt[i, x + 1, y] == 2) //如果小人的下面第二个元素是“★”
                            {
                                dt[i, x + 2, y] = 2;//让五角星变成箱子
                                dt[i, x + 1, y] = 4;// 让箱子变成小人
                                dt[i, x, y] = 0;    //让小人变成空格
                                x++;
                                count++;  //给临时变量赋值作为跳出循环的条件,当count等于xzs时跳出循环
                            }
                            }
                        }
                        else if (s.Key.ToString() == "UpArrow")
                        {
                            if (dt[i, x - 1, y] != 1)
                            {
                                if (dt[i, x - 1, y] == 0)
                                {
                                    temp = dt[i, x - 1, y];
                                    dt[i, x - 1, y] = dt[i, x, y];
                                    dt[i, x, y] = temp;
                                    x--;
                                }
                                else if (dt[i, x - 1, y] == 2 && dt[i, x - 2, y] == 0)
                                {
                                    temp = dt[i, x - 2, y];
                                    dt[i, x - 2, y] = dt[i, x - 1, y];
                                    dt[i, x - 1, y] = temp;
                                    temp = dt[i, x, y];
                                    dt[i, x, y] = dt[i, x - 1, y];
                                    dt[i, x - 1, y] = temp;
                                    x--;
                                }
                                else if (dt[i, x - 2, y] == 3 && dt[i, x - 1, y] == 2) //如果小人的下面第二个元素是“★”
                                {
                                    dt[i, x - 2, y] = 2; //让五角星变成箱子
                                    dt[i, x - 1, y] = 4;// 让箱子变成小人
                                    dt[i, x, y] = 0;    //让小人变成空格
                                    x--;
                                    count++;  //给临时变量赋值作为跳出循环的条件,当count等于xzs时跳出循环
                                }
                            }
                        }
                         else if (s.Key.ToString() == "LeftArrow")
                        {
                            if (dt[i, x, y - 1] != 1)
                            {
                                if (dt[i, x, y - 1] == 0)
                                {
                                    temp = dt[i, x, y - 1];
                                    dt[i, x, y - 1] = dt[i, x, y];
                                    dt[i, x, y] = temp;
                                    y--;
                                }
                                else if (dt[i, x, y - 1] == 2 && dt[i, x, y - 2] == 0)
                                {
                                    temp = dt[i, x, y - 2];
                                    dt[i, x, y - 2] = dt[i, x, y - 1];
                                    dt[i, x, y - 1] = temp;
                                    temp = dt[i, x, y];
                                    dt[i, x, y] = dt[i, x, y - 1];
                                    dt[i, x, y - 1] = temp;
                                    y--;
                                }
                                else if (dt[i, x, y - 2] == 3 && dt[i, x, y - 1] == 2) //如果小人的下面第二个元素是“★”
                                {
                                    dt[i, x, y - 2] = 2; //让五角星变成箱子
                                    dt[i, x, y - 1] = 4;// 让箱子变成小人
                                    dt[i, x, y] = 0;    //让小人变成空格
                                    y--;
                                    count++;  //给临时变量赋值作为跳出循环的条件,当count等于xzs时跳出循环
                                }
                            }
                        }
                        else if (s.Key.ToString() == "RightArrow")
                        {
                            if (dt[i, x, y + 1] != 1)
                            {
                                if (dt[i, x, y + 1] == 0)
                                {
                                    temp = dt[i, x, y + 1];
                                    dt[i, x, y + 1] = dt[i, x, y];
                                    dt[i, x, y] = temp;
                                    y++;
                                }
                                else if (dt[i, x, y + 1] == 2 && dt[i, x, y + 2] == 0)
                                {
                                    temp = dt[i, x, y + 2];
                                    dt[i, x, y + 2] = dt[i, x, y + 1];
                                    dt[i, x, y + 1] = temp;
                                    temp = dt[i, x, y + 1];
                                    dt[i, x, y + 1] = dt[i, x, y];
                                    dt[i, x, y] = temp;
                                    y++;
                                }
                                else if (dt[i, x, y + 2] == 3 && dt[i, x, y + 1] == 2) //如果小人的下面第二个元素是“★”
                                {
                                    dt[i, x, y + 2] = 2; //让五角星变成箱子
                                    dt[i, x, y + 1] = 4;// 让箱子变成小人
                                    dt[i, x, y] = 0;    //让小人变成空格
                                    y++;
                                    count++; //给临时变量赋值作为跳出循环的条件,当count等于xzs时跳出循环
                                }
                            }
                        }
                        else
                        {
    
                        }
                        Console.Clear();  //清屏
                        
                        ditu(dt, i);// 调用ditu函数打印地图
                        if (count==xzs)
                        {
                            Console.WriteLine("恭喜你过关了!");
                            Console.WriteLine("按任意键进入下一关!");
                            Console.ReadKey();
                            x = 1; y = 4;//初始化小人的位置
                            i++;
                            count = 0;
                            xzs = 0;
                            for (int j = 0; j < 10; j++)
                            {
                                for (int k = 0; k < 10; k++)
                                {
    
                                    if (dt[i, j, k] == 3)
                                    {
                                        xzs++;
                                    }
    
                                }
                            }
                        }
                    }
                }
                catch (Exception)
                {
                   // Console.WriteLine("恭喜你全部过关了!");
                    Console.ReadKey();
                }
    
              }
          }
        }
    二百个不间断的重复,只是让我看到了人的命运无法改变这一事实而已。
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  • 原文地址:https://www.cnblogs.com/dlexia/p/4439401.html
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