Arrays和String单元测试
在IDEA中以TDD的方式对String类和Arrays类进行学习
- 测试相关方法的正常,错误和边界情况
- String类
- charAt
- split
- Arrays类
- sort
- binarySearch
- String类
- 码云链接
- 代码
/**
* Created by radish608 on 17-5-10.
*/
import java.util.*;
import org.junit.Test;
import static java.util.Arrays.binarySearch;
public class SAtest {
String teststring1 = "Hello World!";
String teststring2 = " ";
String teststring3 = "boo:and:foo";
String[] teststring4 = new String[3];
String[] teststring5 = new String[3];
@Test
public void StringTester() {
assert teststring1.charAt(0) == 'H' : "error1:charAt";
assert teststring1.charAt(teststring1.length()-1) == '!' : "error2:charAt";
assert teststring2.charAt(0) == teststring2.charAt(teststring2.length()-1) : "error3:charAt";
teststring4 = teststring3.split(":");
teststring5 = teststring3.split("o");
assert teststring4[0].equals("boo") : "error4:split";
assert teststring4[1].equals("and") : "error5:split";
assert teststring4[2].equals("foo"): "error6:split";
assert teststring5[0].equals("b") : "error7:split";
assert teststring5[1].equals("") : "error8:split";
assert teststring5[2].equals(":and:f") : "error9:split";
}
@Test
public void ArraysTester() {
int []testarr1 = { 1, 3, 5, 4, 2, 0};
int []testarr2 = {2, 5, 7, 8, 9, 0, 10, 11, 13, 15, 19};
Arrays.sort(testarr1);
assert testarr1[1] == 1 : "error10:sort";
assert binarySearch(testarr2, 0, testarr2.length-1, 5) == 1 : "error11:binarySearch";
}
}
- 截图
MySort
模拟实现Linux下Sort -t : -k 2的功能。参考 Sort的实现。提交码云链接和代码运行截图。
- 码云链接
- 代码
/**
* Created by radish608 on 17-5-10.
*/
import java.util.*;
public class MySort1 {
public static void main(String[] args) {
String[] toSort = {"aaa:10:1:1",
"ccc:30:3:4",
"bbb:50:4:5",
"ddd:20:5:3",
"eee:40:2:20"};
System.out.println("Before sort:");
for (String str : toSort)
System.out.println(str);
System.out.println("After sort:");
int[] tmp = new int[toSort.length];
String[][] string = new String [toSort.length][4];
for (int i = 0; i < toSort.length; i++) {
string[i] = toSort[i].split(":");
tmp[i] = Integer.parseInt(string[i][1]);
}
Arrays.sort(tmp);
for (int i = 0; i < tmp.length; i++) {
for (int j = 0; j < toSort.length; j++) {
if(tmp[i] == Integer.parseInt(string[j][1])){
System.out.println(toSort[j]);
}
}
}
}
}
- 截图