• [C/CPP系列知识] 那些程序C语言可以编译通过但C++无法编译成功 Write a C program that won’t compile in C++


    http://www.geeksforgeeks.org/write-c-program-wont-compiler-c/

    1) C++中在函数声明之前调用一个函数会引发错误,但是在C中有可能可以。 参考 http://www.cnblogs.com/diegodu/p/4580292.html

    下面的程序可以用gcc编译,但g++无法编译。

    #include<stdio.h>
    int main()
    {
       foo(); // foo() is called before its declaration/definition
    } 
     
    int foo()
    {
       printf("Hello");
       return 0; 
    }

    编译结果:

    diego@ubuntu:~/myProg/geeks4geeks/cpp$ gcc test3.c 
    diego@ubuntu:~/myProg/geeks4geeks/cpp$ g++ test3.c 
    test3.c: In function 'int main()':
    test3.c:4:9: error: 'foo' was not declared in this scope
         foo(); // foo() is called before its declaration/definition

    2) C++中将一个非const指针指向一个const变量是非法的,但在C中是可以的。

    #include <stdio.h>
     
    int main(void)
    {
        int const j = 20;
     
        /* The below assignment is invalid in C++, results in error
           In C, the compiler *may* throw a warning, but casting is
           implicitly allowed */
        int *ptr = &j;  // A normal pointer points to const
     
        printf("*ptr: %d
    ", *ptr);
     
        return 0;
    }

    编译结果:

    diego@ubuntu:~/myProg/geeks4geeks/cpp$ gcc test4.c 
    test4.c: In function 'main':
    test4.c:10:16: warning: initialization discards 'const' qualifier from pointer target type [enabled by default]
         int *ptr = &j;  // A normal pointer points to const
                    ^
    diego@ubuntu:~/myProg/geeks4geeks/cpp$ g++ test4.c 
    test4.c: In function 'int main()':
    test4.c:10:17: error: invalid conversion from 'const int*' to 'int*' [-fpermissive]
         int *ptr = &j;  // A normal pointer points to const
                    ^

    3) C中可以将void* 赋值给其他的指针,如int*, char*等,但是在C++中则需要显示的类型转换。

    #include <stdio.h>
    int main()
    {
       void *vptr;
       int *iptr = vptr; //In C++, it must be replaced with int *iptr=(int *)vptr; 
       return 0;
    }

    编译结果:

    diego@ubuntu:~/myProg/geeks4geeks/cpp$ gcc test5.c 
    diego@ubuntu:~/myProg/geeks4geeks/cpp$ g++ test5.c 
    test5.c: In function 'int main()':
    test5.c:5:17: error: invalid conversion from 'void*' to 'int*' [-fpermissive]
         int *iptr = vptr; //In C++, it must be replaced with int *iptr=(int *)vptr;

    这也就意味着在C++中我们调用malloc时需要显示的转换类型,“int *p = (void *)malloc(sizeof(int)),而在C中不需要。

    4) C++中const变量声明的同时必须赋初值,但C中不需要赋初值。

    #include <stdio.h>
    int main()
    {
        const int a;   // LINE 4
        return 0;
    }

    编译结果:

    diego@ubuntu:~/myProg/geeks4geeks/cpp$ gcc test6.c 
    diego@ubuntu:~/myProg/geeks4geeks/cpp$ g++ test6.c 
    test6.c: In function 'int main()':
    test6.c:4:15: error: uninitialized const 'a' [-fpermissive]
         const int a;   // LINE 4
                   ^

    5) C++中的关键字在C中不可用,如new,delete,explicit等。

    #include <stdio.h>
    int main(void)
    {
        int new = 5;  // new is a keyword in C++, but not in C
        printf("%d", new);
    }

    6) C++有着更加严格的类型检查。C++无法通过编译,有error,C中仅仅报warning

    #include <stdio.h>
    int main()
    {
        char *c = 333;
        printf("c = %u", c);
        return 0;
    }

    编译结果:

    diego@ubuntu:~/myProg/geeks4geeks/cpp$ gcc test7.c 
    test7.c: In function 'main':
    test7.c:4:15: warning: initialization makes pointer from integer without a cast [enabled by default]
         char *c = 333;
                   ^
    test7.c:5:5: warning: format '%u' expects argument of type 'unsigned int', but argument 2 has type 'char *' [-Wformat=]
         printf("c = %u", c);
         ^
    diego@ubuntu:~/myProg/geeks4geeks/cpp$ g++ test7.c 
    test7.c: In function 'int main()':
    test7.c:4:15: error: invalid conversion from 'int' to 'char*' [-fpermissive]
         char *c = 333;
                   ^
    test7.c:5:23: warning: format '%u' expects argument of type 'unsigned int', but argument 2 has type 'char*' [-Wformat=]
         printf("c = %u", c);
                           ^

    7) C++变量可以在任意位置定义,但是C中必须是一个语句块开始的地方。(gcc 中可以编译。。)

    #include <stdio.h>
    int main()
    {
        int i;
        i=5;
        i++;
        int j;
        return 0;
    }

    8) C++存在loop variable,C中不存在。

    #include <stdio.h>
    int main()
    {
    for(int i=0; i<5; i++)
      ;  
        
    return 0;
    }

    9) C++ main函数必须返回int,C可以返回void

    #include <stdio.h>
    void main (int argc, char *argv[])
    {
         printf("bye
    ");
    }

    编译结果:

    diego@ubuntu:~/myProg/geeks4geeks/cpp$ gcc test9.c 
    diego@ubuntu:~/myProg/geeks4geeks/cpp$ g++ test9.c 
    test9.c:2:34: error: '::main' must return 'int'
     void main (int argc, char *argv[])
                                      ^
    diego@ubuntu:~/myProg/geeks4geeks/cpp$ 

     

     

     

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  • 原文地址:https://www.cnblogs.com/diegodu/p/4580474.html
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