Given a string s consists of upper/lower-case alphabets and empty space characters ' '
, return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s = "Hello World"
,
return 5
.
1 class Solution { 2 public: 3 int lengthOfLastWord(const char *s) { 4 int total_len = strlen(s); 5 if (total_len == 0) return 0; 6 int ret = 0, i = total_len - 1; 7 while (i >= 0 && s[i] == ' ') --i; 8 while (i >= 0 && s[i] != ' ') { 9 ++ret; 10 --i; 11 } 12 return ret; 13 } 14 };
按题意数就可以了..