• 敌兵布阵 HDU 1166


    题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=1166

    题目简单,直接套用线段树模板。

    代码如下:

    #include <iostream>
    #include <cstdlib>
    #include <cstdio>
    #include <algorithm>
    #include <vector>
    #include <queue>
    #include <cmath>
    #include <map>
    #include <stack>
    #include <cstring>
    using namespace std;
    #define INF 0xfffffff
    #define maxn 51000
    #define lson rt<<1
    #define rson rt<<1|1
    int A[maxn];
    
    struct node
    {
      int l, r, s;
    } tree[maxn<<2];
    
    void build(int l, int r, int rt)
    {
        tree[rt].l = l;
        tree[rt].r = r;
    
        if(l == r)
        {
            tree[rt].s = A[l];
            return ;
        }
    
        int mid = (l+r)/2;
    
        build(l, mid, lson);
        build(mid+1, r, rson);
    
        tree[rt].s = tree[lson].s + tree[rson].s;
    }
    
    void update(int pos, int val, int rt)
    {
       tree[rt].s += val;
    
       if(tree[rt].l == tree[rt].r)
           return ;
    
        int mid = (tree[rt].l + tree[rt].r)/2;
    
        if(pos<=mid) update(pos, val, lson);
        else  update(pos, val, rson);
    }
    
    int query(int l, int r, int rt)
    {
        if(tree[rt].l == l && r == tree[rt].r)
            return tree[rt].s;
    
         int mid = (tree[rt].l + tree[rt].r)/2;
         if(r<=mid) return query(l, r, lson);
         else if(l>mid) return query(l, r, rson);
         else
         {
            int lsum, rsum;
            lsum = query(l, mid, lson);
            rsum = query(mid+1, r, rson);
            return lsum+rsum;
         }
    }
    
    int main()
    {
        int T, n, a, b, cnt=1;
        char op[20];
    
        scanf("%d", &T);
    
        while(T --)
        {
            scanf("%d", &n);
    
            for(int i=1; i<=n; i++)
                scanf("%d", &A[i]);
    
            build(1, n, 1);
    
             printf("Case %d:
    ",cnt++);
    
            while(scanf("%s", op),strcmp(op, "End"))
            {
    
                scanf("%d %d", &a, &b);
    
                if(op[0] == 'Q')
                {
                    int ans = query(a, b, 1);
                    printf("%d
    ", ans);
                    continue;
                }
    
                if(op[0] == 'A')
                    update(a, b, 1);
                else
                    update(a, -b, 1);
            }
    
        }
        return 0;
    }
    View Code
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  • 原文地址:https://www.cnblogs.com/daydayupacm/p/5679035.html
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