错误的代码
HttpClient httpclient = new DefaultHttpClient();
HttpUriRequest request = new HttpGet(uri);
HttpParams p = new BasicHttpParams();
p.setParameter("param", "value");
request.setParams(p);
request.setHeader("Accept", "application/json, text/javascript, */*; q=0.01");
HttpResponse response = null;
try {
response = httpclient.execute(request);
} catch (ClientProtocolException e) {
e.printStackTrace();
}
解决方案
HttpClient httpclient = new DefaultHttpClient();
String url = "http://example.com";
List<NameValuePair> params = new ArrayList<NameValuePair>();
params.add( new BasicNameValuePair( "param", "value" ) );
URI uri = new URI( url + "?" + URLEncodedUtils.format( params, "utf-8" );
HttpUriRequest request = new HttpGet(uri);
request.setHeader("Accept", "application/json, text/javascript, */*; q=0.01");
HttpResponse response = null;
try {
response = httpclient.execute(request);
} catch (ClientProtocolException e) {
e.printStackTrace();
}