• java如何实现python的urllib.quote(str,safe='/')


    最近需要将一些python代码转成java,遇到url编码

    urllib.quote(str,safe='/')

    但java中URLEncoder.encode(arg, Constant.UTF_8)会将'/'转成%2F

    网上查了一下 java没见到类似的safe方式,只好自己实现一个类

    package com.ppc.spider.fc.util;
    import java.io.ByteArrayOutputStream;
    import java.io.BufferedWriter;
    import java.io.OutputStreamWriter;
    import java.io.IOException;
    import java.io.UnsupportedEncodingException;
    import java.net.URLDecoder;
    import java.io.CharArrayWriter;
    import java.nio.charset.Charset;
    import java.nio.charset.IllegalCharsetNameException;
    import java.nio.charset.UnsupportedCharsetException ;
    import java.util.BitSet;
    import java.security.AccessController;
    import sun.security.action.GetPropertyAction;
    
    public class UrlSafeEncoder {
    
        static BitSet dontNeedEncoding;
        static final int caseDiff = ('a' - 'A');
        static String dfltEncName = null;
    
        static {
    
            /* The list of characters that are not encoded has been
             * determined as follows:
             *
             * RFC 2396 states:
             * -----
             * Data characters that are allowed in a URI but do not have a
             * reserved purpose are called unreserved.  These include upper
             * and lower case letters, decimal digits, and a limited set of
             * punctuation marks and symbols.
             *
             * unreserved  = alphanum | mark
             *
             * mark        = "-" | "_" | "." | "!" | "~" | "*" | "'" | "(" | ")"
             *
             * Unreserved characters can be escaped without changing the
             * semantics of the URI, but this should not be done unless the
             * URI is being used in a context that does not allow the
             * unescaped character to appear.
             * -----
             *
             * It appears that both Netscape and Internet Explorer escape
             * all special characters from this list with the exception
             * of "-", "_", ".", "*". While it is not clear why they are
             * escaping the other characters, perhaps it is safest to
             * assume that there might be contexts in which the others
             * are unsafe if not escaped. Therefore, we will use the same
             * list. It is also noteworthy that this is consistent with
             * O'Reilly's "HTML: The Definitive Guide" (page 164).
             *
             * As a last note, Intenet Explorer does not encode the "@"
             * character which is clearly not unreserved according to the
             * RFC. We are being consistent with the RFC in this matter,
             * as is Netscape.
             *
             */
    
            dontNeedEncoding = new BitSet(256);
            int i;
            for (i = 'a'; i <= 'z'; i++) {
                dontNeedEncoding.set(i);
            }
            for (i = 'A'; i <= 'Z'; i++) {
                dontNeedEncoding.set(i);
            }
            for (i = '0'; i <= '9'; i++) {
                dontNeedEncoding.set(i);
            }
            dontNeedEncoding.set(' '); /* encoding a space to a + is done
                                        * in the encode() method */
            dontNeedEncoding.set('-');
            dontNeedEncoding.set('_');
            dontNeedEncoding.set('.');
            dontNeedEncoding.set('*');
    
            dfltEncName = AccessController.doPrivileged(
                new GetPropertyAction("file.encoding")
            );
        }
    
        /**
         * You can't call the constructor.
         */
        private UrlSafeEncoder() { }
        /**
         * Translates a string into {@code application/x-www-form-urlencoded}
         * format using a specific encoding scheme. This method uses the
         * supplied encoding scheme to obtain the bytes for unsafe
         * characters.
         * <p>
         * <em><strong>Note:</strong> The <a href=
         * "http://www.w3.org/TR/html40/appendix/notes.html#non-ascii-chars">
         * World Wide Web Consortium Recommendation</a> states that
         * UTF-8 should be used. Not doing so may introduce
         * incompatibilities.</em>
         *
         * @param   s   {@code String} to be translated.
         * @param   enc   The name of a supported
         *    <a href="../lang/package-summary.html#charenc">character
         *    encoding</a>.
         * @return  the translated {@code String}.
         * @exception  UnsupportedEncodingException
         *             If the named encoding is not supported
         * @see URLDecoder#decode(java.lang.String, java.lang.String)
         * @since 1.4
         */
        public static String encode(String s, String enc,char safe)
            throws UnsupportedEncodingException {
            dontNeedEncoding.set(safe);
            boolean needToChange = false;
            StringBuffer out = new StringBuffer(s.length());
            Charset charset;
            CharArrayWriter charArrayWriter = new CharArrayWriter();
    
            if (enc == null)
                throw new NullPointerException("charsetName");
    
            try {
                charset = Charset.forName(enc);
            } catch (IllegalCharsetNameException e) {
                throw new UnsupportedEncodingException(enc);
            } catch (UnsupportedCharsetException e) {
                throw new UnsupportedEncodingException(enc);
            }
    
            for (int i = 0; i < s.length();) {
                int c = (int) s.charAt(i);
                //System.out.println("Examining character: " + c);
                if (dontNeedEncoding.get(c)) {
                    if (c == ' ') {
                        c = '+';
                        needToChange = true;
                    }
                    //System.out.println("Storing: " + c);
                    out.append((char)c);
                    i++;
                } else {
                    // convert to external encoding before hex conversion
                    do {
                        charArrayWriter.write(c);
                        /*
                         * If this character represents the start of a Unicode
                         * surrogate pair, then pass in two characters. It's not
                         * clear what should be done if a bytes reserved in the
                         * surrogate pairs range occurs outside of a legal
                         * surrogate pair. For now, just treat it as if it were
                         * any other character.
                         */
                        if (c >= 0xD800 && c <= 0xDBFF) {
                            /*
                              System.out.println(Integer.toHexString(c)
                              + " is high surrogate");
                            */
                            if ( (i+1) < s.length()) {
                                int d = (int) s.charAt(i+1);
                                /*
                                  System.out.println("	Examining "
                                  + Integer.toHexString(d));
                                */
                                if (d >= 0xDC00 && d <= 0xDFFF) {
                                    /*
                                      System.out.println("	"
                                      + Integer.toHexString(d)
                                      + " is low surrogate");
                                    */
                                    charArrayWriter.write(d);
                                    i++;
                                }
                            }
                        }
                        i++;
                    } while (i < s.length() && !dontNeedEncoding.get((c = (int) s.charAt(i))));
    
                    charArrayWriter.flush();
                    String str = new String(charArrayWriter.toCharArray());
                    byte[] ba = str.getBytes(charset);
                    for (int j = 0; j < ba.length; j++) {
                        out.append('%');
                        char ch = Character.forDigit((ba[j] >> 4) & 0xF, 16);
                        // converting to use uppercase letter as part of
                        // the hex value if ch is a letter.
                        if (Character.isLetter(ch)) {
                            ch -= caseDiff;
                        }
                        out.append(ch);
                        ch = Character.forDigit(ba[j] & 0xF, 16);
                        if (Character.isLetter(ch)) {
                            ch -= caseDiff;
                        }
                        out.append(ch);
                    }
                    charArrayWriter.reset();
                    needToChange = true;
                }
            }
    
            return (needToChange? out.toString() : s);
        }
    }

    验证下 基本ok

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  • 原文地址:https://www.cnblogs.com/davidwang456/p/9476384.html
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