编程题#2
来源: POJ (Coursera声明:在POJ上完成的习题将不会计入Coursera的最后成绩。)
注意: 总时间限制: 1000ms 内存限制: 65536kB
描述
写一个自己的 CMyistream_iterator 模板,使之能和 istream_iterator 模板达到一样的效果,即:
输入:
79 90 20 hello me
输出:
79
79,90,20
hello,me
#include <iostream> #include <string> using namespace std; // 在此处补充你的代码 int main() { CMyistream_iterator<int> inputInt(cin); int n1,n2,n3; n1 = * inputInt; //读入 n1 int tmp = * inputInt; cout << tmp << endl; inputInt ++; n2 = * inputInt; //读入 n2 inputInt ++; n3 = * inputInt; //读入 n3 cout << n1 << "," << n2<< "," << n3 << endl; CMyistream_iterator<string> inputStr(cin); string s1,s2; s1 = * inputStr; inputStr ++; s2 = * inputStr; cout << s1 << "," << s2 << endl; return 0; }
输入
79 90 20 hello me
输出
79
79,90,20
hello,me
样例输入
79 90 20 hello me
样例输出
79 79,90,20 hello,me
提示
istream_iterator模版使用说明:
其构造函数执行过程中就会要求输入,然后每次执行++,则读取输入流中的下一个项目,执行 * 则返回上次从输入流中读取的项目。例如,下面程序运行时,就会等待用户输入数据,输入数据后程序才会结束:
#include <iostream> #include <iterator> using namespace std; int main() { istream_iterator<int> inputInt(cin); return 0; }
下面程序运行时,如果输入 12 34 程序输出结果是: 12,12
#include <iostream> #include <iterator> using namespace std; int main() { istream_iterator<int> inputInt(cin); cout << * inputInt << "," << * inputInt << endl; return 0; }
下面程序运行时,如果输入 12 34 56程序输出结果是: 12,56
#include <iostream> #include <iterator> using namespace std; int main() { istream_iterator<int> inputInt(cin); cout << * inputInt << "," ; inputInt ++; inputInt ++; cout << * inputInt; return 0; }
#include <iostream> #include <string> using namespace std; // 在此处补充你的代码 template <class T> class CMyistream_iterator { public: CMyistream_iterator(istream &input):is(input) { is>>a; } T operator *() { return a; } void operator ++(int) { is>>a; } private: T a; istream & is; }; int main() { CMyistream_iterator<int> inputInt(cin); int n1,n2,n3; n1 = * inputInt; //读入 n1 int tmp = * inputInt; cout << tmp << endl; inputInt ++; n2 = * inputInt; //读入 n2 inputInt ++; n3 = * inputInt; //读入 n3 cout << n1 << "," << n2<< "," << n3 << endl; CMyistream_iterator<string> inputStr(cin); string s1,s2; s1 = * inputStr; inputStr ++; s2 = * inputStr; cout << s1 << "," << s2 << endl; return 0; }