import os def fetch(data): print(' 33[1;41m这是查询功能 33[0m') print(' 33[1;41m用户数据 33[0m', data) backend_data = 'backend %s' %data with open ('lala.conf', 'r', encoding = 'utf-8') as read_f: tag = False ret = [] for read_line in read_f: if read_line.strip() == backend_data: tag = True continue if tag and read_line.startswith('backend'): break if tag: ret.append(read_line) return ret def add(): pass def change(data): print("这是修改功能") backend = data[0]['backend'] #文件中的一条记录 www.oldboy1.org backend_data = 'backend %s' %backend old_service_recode = '%sservice %s %s weight %s maxconn %s ' % (' '*8,data[0]['record']['service'], data[0]['record']['service'], data[0]['record']['weight'], data[0]['record']['maxconn']) new_service_recode = '%sservice %s %s weight %s maxconn %s ' % (' ' * 8, data[1]['record']['service'], data[1]['record']['service'], data[1]['record']['weight'], data[1]['record']['maxconn']) print('用户想要修改的记录是%s' % old_service_recode) res = fetch(backend) if not res or old_service_recode not in res: return '你要修改的文件不存在' else: index1 = res.index(old_service_recode) res[index1] = new_service_recode res.insert(0, '%s '%backend_data) with open('lala.conf', 'r', encoding='utf-8') as read_f, open('lala_new.conf', 'w', encoding = 'utf8') as write_f: tag = False has_write = False for read_line in read_f: if read_line.strip() == backend_data: tag = True continue if tag and read_line.startswith('backend'): tag = False if not tag: write_f.write(read_line) else: if not has_write: for record in res: write_f.write(record) has_write = True os.rename('lala.conf', 'sb') os.rename('lala_new.conf', 'lala.conf') os.remove('sb') def delete(): pass if __name__ == '__main__': msg = ''' 1: 查询 2: 添加 3: 修改 4: 删除 5: 退出 ''' msg_dic = { '1': fetch, '2': add, '3': change, '4': delete } while True: print(msg) choice = input('请输入你的选项:').strip() if not choice:continue #如果输入为空或者回车,将重新输入 if choice == '5': break data = input('请输入你的数据:').strip() if choice != '1': data = eval(data) res = msg_dic[choice](data) print(res)
数据输入:[{'backend':'www.oldboy1.org', 'record': {'service':'2.2.2.4','weight':20,'maxconn':30000}},{'backend':'www.oldboy1.org','record': {'service':'2.2.2.5','weight':30,'maxconn':4000}}]
程序的解耦
把程序中间复杂的重复代码,封装到一个函数中去
import os def fetch(data): print(' 33[1;41m这是查询功能 33[0m') print(' 33[1;41m用户数据 33[0m', data) backend_data = 'backend %s' %data return func(backend_data) def func(backend_data, res = None, type = 'fetch'): if type == 'fetch': with open ('lala.conf', 'r', encoding = 'utf-8') as read_f: tag = False ret = [] for read_line in read_f: if read_line.strip() == backend_data: tag = True continue if tag and read_line.startswith('backend'): break if tag: ret.append(read_line) return ret elif type =='change': with open('lala.conf', 'r', encoding='utf-8') as read_f, open('lala_new.conf', 'w', encoding='utf8') as write_f: tag = False has_write = False for read_line in read_f: if read_line.strip() == backend_data: tag = True continue if tag and read_line.startswith('backend'): tag = False if not tag: write_f.write(read_line) else: if not has_write: for record in res: write_f.write(record) has_write = True os.rename('lala.conf', 'sb') os.rename('lala_new.conf', 'lala.conf') os.remove('sb') def add(): pass def change(data): print("这是修改功能") backend = data[0]['backend'] #文件中的一条记录 www.oldboy1.org backend_data = 'backend %s' %backend old_service_recode = '%sservice %s %s weight %s maxconn %s ' % (' '*8,data[0]['record']['service'], data[0]['record']['service'], data[0]['record']['weight'], data[0]['record']['maxconn']) new_service_recode = '%sservice %s %s weight %s maxconn %s ' % (' ' * 8, data[1]['record']['service'], data[1]['record']['service'], data[1]['record']['weight'], data[1]['record']['maxconn']) print('用户想要修改的记录是%s' % old_service_recode) res = fetch(backend) if not res or old_service_recode not in res: return '你要修改的文件不存在' else: index1 = res.index(old_service_recode) res[index1] = new_service_recode res.insert(0, '%s '%backend_data) func(backend_data,res = res, type = 'change') def delete(): pass if __name__ == '__main__': msg = ''' 1: 查询 2: 添加 3: 修改 4: 删除 5: 退出 ''' msg_dic = { '1': fetch, '2': add, '3': change, '4': delete } while True: print(msg) choice = input('请输入你的选项:').strip() if not choice:continue #如果输入为空或者回车,将重新输入 if choice == '5': break data = input('请输入你的数据:').strip() if choice != '1': data = eval(data) res = msg_dic[choice](data) print(res)