long long H( int n ) {
long long res = 0;
for( int i = 1; i <= n; i++ )
res = res + n / i;
return res;
}
Yes, my error was that I was using the integer divisions only. However, you are given n, you have to find H(n) as in my code.
Input
Input starts with an integer T (≤ 1000), denoting the number of test cases.
Each case starts with a line containing an integer n (1 ≤ n < 231).
Output
For each case, print the case number and H(n) calculated by the code.
Sample Input
11
1
2
3
4
5
6
7
8
9
10
2147483647
Sample Output
Case 1: 1
Case 2: 3
Case 3: 5
Case 4: 8
Case 5: 10
Case 6: 14
Case 7: 16
Case 8: 20
Case 9: 23
Case 10: 27
Case 11: 46475828386
题意:求H(n);
#include<map> #include<stack> #include<queue> #include<math.h> #include<vector> #include<string> #include<stdio.h> #include<iostream> #include<string.h> #include<algorithm> #define mem(a,b) memset(a,b,sizeof(a)) #define maxn 10000001 #define maxm 1000000000005 #define mod 1000000007 #define ll long long #define inf 0x3f3f3f3f using namespace std; int main(){ int t,test=0;scanf("%d",&t); while(t--){ ll x;scanf("%lld",&x); ll n=sqrt(x*1.0); ll ans=0; for(int i=1;i<=n;i++){ans+=x/i;} for(int i=1;i<=n;i++){ ans+=(x/i-x/(i+1))*i; } if(n==x/n)ans-=n; printf("Case %d: %lld ",++test,ans); } }