• 2d中水波的原理与实现


    不废话,直接上代码

    【xna 中调用】

     

    GraphicsDevice.Textures[1] = wa;

    // TODO: Add your drawing code here
    times += (float)gameTime.ElapsedGameTime.Milliseconds;
    eff.CurrentTechnique = eff.Techniques[0];
    eff.Parameters["times"].SetValue(times);
    //eff.Parameters["point"].SetValue(point);

    spriteBatch.Begin(SpriteSortMode.Deferred,
    BlendState.AlphaBlend,
    SamplerState.LinearWrap,
    DepthStencilState.Default,
    RasterizerState.CullNone,
    eff);
    spriteBatch.Draw(tex, Vector2.Zero, Color.White);
    spriteBatch.End();

    【shader】

    float times;
    sampler tex_sampler:register(s0);
    sampler tex_ripple:register(s1);

    struct Input
    {
    float2 uv:TEXCOORD0;
    };

    float4 PShader(Input input) : COLOR0
    {
    //==================================================================================
    //波动效果
    float4 color = float4(0,0,0,0);
    float2 backgroundUv = input.uv;

    //mark #1
    //当前像素点显示的纹理上的UV坐标
    //是根据原始显示的纹理UV计偏移
    //其实就是纹理上的点做园周运动
    //原理:像素点x ,uv为(x,y)
    //修改像素点显示的纹理
    //uv => 新的uv为(x*(1+ sin(x * Increment)),y*(1+cos(y* Increment)));

    backgroundUv.x += sin(times / 500.f + backgroundUv.x * 15) * 0.005;
    backgroundUv.y += cos(times / 500.f + backgroundUv.y * 15) * 0.005;
    color = tex2D(tex_sampler,backgroundUv);

    //==================================================================================
    //原理同上
    //水底的光效果
    float4 shading = float4(0,0,0,0);
    float2 lightUv = input.uv;

    //同上 mark #1
    input.uv.x += cos(times / 100.f + input.uv.x * 50 ) * 0.01 ;
    input.uv.y += sin(times / 100.f + input.uv.y * 50) * 0.01 ;
    shading = tex2D(tex_ripple,input.uv);

    //让一张白图呈沅的颜色
    shading.r *= 0.7f;
    shading.g *= 0.59f;
    shading.b *= 0.11f;
    //==================================================================================

    return color + shading * 0.3 ;
    }

    technique Technique1
    {
    pass Pass1
    {
    PixelShader = compile ps_2_0 PShader();
    }
    }

    由于系统只支持2M之下的附件,索要源代码请联系QQ:371741579

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  • 原文地址:https://www.cnblogs.com/czjone/p/2335919.html
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