• Codeforces 600E Lomsat gelral (树上启发式合并)


    题目链接 Lomsat gelral

    占坑……等深入理解了再来补题解……

    #include <bits/stdc++.h>
    
    using namespace std;
    
    #define rep(i, a, b)    for (int i(a); i <= (b); ++i)
    
    typedef long long LL;
    
    const int N = 600010;
    
    int n;
    int cc[N], col[N], sz[N], son[N];
    LL ans[N];
    
    vector <int> v[N];
    
    void getsize(int x, int fa){
            sz[x] = 1;
            for (auto u : v[x]){
                    if (u == fa) continue;
                    getsize(u, x); sz[x] += sz[u];
                    if (!son[x] || sz[u] > sz[son[x]]) son[x] = u;
            }
    }
    
    bool skip[N];
    LL sum = 0;
    int cx = 0;
    int x, y;
    
    void edt(int x, int fa, int k){
            cc[col[x]] += k;
            if (k > 0 && cc[col[x]] >= cx){
                    if (cc[col[x]] > cx)
                            sum = 0, cx = cc[col[x]];
                    sum += col[x];
            }
            
            for (auto u : v[x]){
            if (u == fa || skip[u]) continue;
            edt(u, x, k);
        }
        
    }
    
    void dfs(int x, int fa, int kep = 0){
            for (auto u : v[x]){
                    if (u == fa || u == son[x]) continue;
                    dfs(u, x, 0);
            }
            
            if (son[x]) dfs(son[x], x, 1), skip[son[x]] = 1;
            edt(x, fa, 1);
            
            ans[x] = sum;
            if (son[x]) skip[son[x]] = 0;
            if (!kep) edt(x, fa, -1), cx = sum = 0;
    }
    
    int main(){
        
        scanf("%d", &n);
        rep(i, 1, n) scanf("%d", col + i);
        
        rep(i, 1, n - 1){
            scanf("%d%d", &x, &y);
            v[x].push_back(y);
            v[y].push_back(x);
        }
        
        getsize(1, 0);
        dfs(1, 0, 0);
        
        rep(i, 1, n) printf("%lld
    ", ans[i]);
        return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/cxhscst2/p/6798639.html
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