• 策略模式


    策略模式(Strategy)。定义一系列的算法,把它们一个个封装起来,而且使它们可相互替换。本模式使得算法的变化可独立于使用它的客户。

    package gof23;
    
    public class StrategyTest {
    	public static void main(String[] args) {
    		CashContext cc = null;
    		cc = new CashContext("正常收费");
    		System.out.println("收费为:" + cc.getResult(2000) +"元");
    		cc = new CashContext("满300返100");
    		System.out.println("收费为:" + cc.getResult(2000) +"元");
    		cc = new CashContext("打8折");
    		System.out.println("收费为:" + cc.getResult(2000) +"元");
    	}
    }
    
    class CashContext {
    	private CashSuper cs = null;
    	public CashContext(String type) {
    		switch(type) {
    		case "正常收费":
    			CashNormal cs0 = new CashNormal();
    			cs = cs0;
    			break;
    		case "满300返100":
    			CashReturn cs1 = new CashReturn(300, 100);
    			cs= cs1;
    			break;
    		case "打8折":
    			CashRebate cs2 = new CashRebate(0.8);
    			cs = cs2;
    			break;
    		}
    	}
    	
    	public double getResult(double money) {
    		return cs.acceptCash(money);
    	}
    }
    
    abstract class CashSuper {
    	public abstract double acceptCash(double money);
    }
    
    /*
     * 正常收费。原价返回
     */
    class CashNormal extends CashSuper {
    
    	@Override
    	public double acceptCash(double money) {
    		return money;
    	}
    	
    }
    
    /*
     * 打折收费。初始化时,须要输入折扣率。如0.8
     */
    class CashRebate extends CashSuper {
    	private double moneyRebate = 1d;
    	public CashRebate(double moneyRebate) {
    		this.moneyRebate = moneyRebate;
    	}
    	@Override
    	public double acceptCash(double money) {
    		return money * moneyRebate;
    	}
    	
    }
    
    /*
     * 返利收费。初始化时必须输入返利条件和返利值。比方满300返100,
     * 则moneyCondition为300,moneyReturn为100
     */
    class CashReturn extends CashSuper {
    	private double moneyCondition = 0.0d;
    	private double moneyReturn = 0.0d;
    	public CashReturn(double moneyCondition, double moneyReturn) {
    		this.moneyCondition = moneyCondition;
    		this.moneyReturn = moneyReturn;
    	}
    	@Override
    	public double acceptCash(double money) {
    		double result  = money;
    		if(result > moneyCondition)
    			result = money - Math.floor(money / moneyCondition) * moneyReturn;
    		return result;
    	}
    	
    }
    

    执行结果为:

    收费为:2000.0元
    收费为:1400.0元
    收费为:1600.0元
    


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  • 原文地址:https://www.cnblogs.com/cxchanpin/p/6789222.html
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