• 【LEETCODE】40、1051. Height Checker


    package y2019.Algorithm.array;
    
    /**
     * @ProjectName: cutter-point
     * @Package: y2019.Algorithm.array
     * @ClassName: HeightChecker
     * @Author: xiaof
     * @Description: 1051. Height Checker
     * Students are asked to stand in non-decreasing order of heights for an annual photo.
     * Return the minimum number of students not standing in the right positions.
     * (This is the number of students that must move in order for all students to be standing in non-decreasing order of height.)
     * Input: [1,1,4,2,1,3]
     * Output: 3
     * Explanation:
     * Students with heights 4, 3 and the last 1 are not standing in the right positions.
     * @Date: 2019/7/3 9:19
     * @Version: 1.0
     */
    public class HeightChecker {
    
        public int solution(int[] heights) {
    
            //首先排个序,然后比较一下就可以了!,来个快排吧
            int[] array = new int[heights.length];
    
            for(int i = 0; i < array.length; ++i) {
                array[i] = heights[i];
            }
    
            quikSort1(array, 0, array.length);
    
            //比较不同的位置
            int result = 0;
            for(int j = 0; j < array.length; ++j) {
                if(array[j] != heights[j]) {
                    result++;
                }
            }
    
            return result;
        }
    
        private void quikSort1(int array[], int start, int end) {
            if(start < end) {
                int mid = this.hoarePartition(array, start, end);
                quikSort1(array, start, mid);
                quikSort1(array, mid + 1, end);
            }
        }
    
        private int hoarePartition(int[] array, int start, int end) {
            //对区间进行排序
            int midValue = array[start];
            int index1 = start, index2 = end;
            //为了避免自己重复比较
            do {
                //左边查找比mid值大的
                do {
                    ++index1;
                } while(index1 < end && array[index1] < midValue);
    
                //找到比mid小的值
                do {
                    --index2;
                } while(index2 > start && array[index2] > midValue);
    
                //交换数据
                if(index1 < index2) {
                    int temp = array[index1];
                    array[index1] = array[index2];
                    array[index2] = temp;
                }
    
            } while(index1 < index2);
    
            //最后我们把坑填到中间位置,因为index1和index2错开位置了,我们交换回来
    //        int temp = array[index1];
    //        array[index1] = array[index2];
    //        array[index2] = temp;
            //填坑
            array[start] = array[index2];
            array[index2] = midValue;
    
            return index2;
        }
    
        public static void main(String args[]) {
            int A[] = {7,4,5,6,4,2,1,4,6,5,4,8,3,1,8,2,7,6,3,2};
            int A1[] = {1,1,4,2,1,3};
            int A2[] = {1,4,3,2};
            HeightChecker fuc = new HeightChecker();
            System.out.println(fuc.solution(A2));
        }
    
    
    }
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  • 原文地址:https://www.cnblogs.com/cutter-point/p/11128146.html
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