str内多少个，判断是否空格，方法删除改变本身，赋值给其他本身不改变，斐波那契时间n空间1,简单递归

# def countnum(a):
#     di_num = 0
#     ph_num =0
#     sp_num = 0
#     el_num = 0
#     for i in a:
#         if i.isdigit():
#             di_num +=1
#         elif i.isalpha():
#             ph_num +=1
#         elif i.isspace():
#             sp_num +=1
#         else:
#             el_num +=1
#     return (di_num,ph_num,sp_num,el_num)
# ret = countnum("456465hhhgggg   $%^&")
# print(ret)
# def islensize(args):
#     print(args)
#     if len(args) > 5:
#         return True
#     else:
#         return False
# print(islensize(("456122",45,45,12,12,12)))
# def isnone(args):
#     for i in args:
#         if i is "":
#             return True
#         print("ok")
# print(isnone([11,22,"",444,"",4445,]))
# def has_space(arg):
#     for i in arg:
#         if i.isspace():
#             return True
#         print("ok")
#     return False
"""
ret = False
for i in arg:
    if i.isspace():
        ret = Ture
        break#注意提前终止不必要的循环
return ret
"""
# print(has_space("456"))
# print(isnone([11,22,"",6]))
# def fun5(args):
#     if len(args) >2 :
#         result = args[0:2]
#         return result
#     else:
#         return args
# print(fun5([22,44,55,11,66]))
# def ff(args):#删除偶数会改变初始列表不可用
#     result = []
#     for i in range(0,len(args)):
#         if i %2 ==1:
#             result.append(args[i])
#     return result
# print(ff([11,22,44,66,77,77]))
# def ff_dict(dic):
#     for k,v in dic.items():
#         if len(v) > 2:
#             dic[k] = v[0:2]
#     return dic#可以不return，因为dic自身已经改变，省内存
# print(ff_dict({"k1":"fdgfdfg","k2":[11,22,33],"k3":[11,33]}))
#1 1 2 3 5 8 13
def fib(n):
    first = 0
    second = 1
    i=1
    while i<n:
        third = first+second
        first = second
        second = third
        i +=1
    return third
print(fib(10))

#递归，斐波那契数列
def fib(n,depth,a1,a2):
    if depth == n:
        return a1
    a3 = a1 + a2
    r = fib(n,depth+1,a2,a3)#注意需要接收返回值
    return r
ret = fib(10,1,0,1)
print(ret)

def q(arg):
    #isinstance 判断是否是字符串，列表，元组...
    if isinstance(arg,str) or isinstance(arg,list) or isinstance(arg,tuple):
        print(arg)
    return None
#函数传参传的是引用
def w(a):#例，删除，的是li自己变了.赋值不变是自己生成一个
    del a[2:]
    a = 123
li = [11,22,33,44]
w(li)
print(li)