• BZOJ1832: [AHOI2008]聚会


    题目:http://www.lydsy.com/JudgeOnline/problem.php?id=1832

    直接找三个点lca就可以了。这叫lca模版题。

    #include<cstring>
    #include<iostream>
    #include<cstdio>
    #include<map>
    #include<cmath>
    #include<algorithm>
    #define rep(i,l,r) for (int i=l;i<=r;i++)
    #define down(i,l,r) for (int i=l;i>=r;i--)
    #define clr(x,y) memset(x,y,sizeof(x))
    #define maxn 500500
    #define inf 2000000000
    #define mm 1000000007
    using namespace std;
    struct data{int obj,pre;
    }e[maxn*2];
    int head[maxn],bin[22],a[maxn],d[maxn],fa[maxn][22],tot,n,m;
    int read(){
        int x=0,f=1; char ch=getchar();
        while (!isdigit(ch)) {if (ch=='-') f=-1; ch=getchar();}
        while (isdigit(ch)) {x=x*10+ch-'0'; ch=getchar();}
        return x*f;
    }
    void insert(int x,int y){
        e[++tot].obj=y; e[tot].pre=head[x]; head[x]=tot; 
    }
    void dfs(int u){
        rep(i,1,20) if (d[u]>=bin[i]) fa[u][i]=fa[fa[u][i-1]][i-1];
        for (int j=head[u];j;j=e[j].pre){
            int v=e[j].obj;
            if (v!=fa[u][0]) {
                fa[v][0]=u; d[v]=d[u]+1; 
                dfs(v);
            }
        }
    }
    int lca(int x,int y){
        if (d[x]<d[y]) swap(x,y);
        int t=d[x]-d[y];
        rep(i,0,20) if (t&bin[i]) x=fa[x][i];
        down(i,20,0) if (fa[x][i]!=fa[y][i]) x=fa[x][i],y=fa[y][i];
        if (x==y) return x;
        return fa[x][0];
    }
    int main(){
        //freopen("in.txt","r",stdin);
        bin[0]=1; rep(i,1,20) bin[i]=bin[i-1]*2;
        n=read(); m=read();
        rep(i,1,n-1){
            int x=read(),y=read();
            insert(x,y); insert(y,x);
        }
        d[1]=0;
        dfs(1);
        rep(i,1,m) {
            int ans=inf,ans2;
            int x=read(),y=read(),z=read(),t1=lca(x,y),t2=lca(y,z),t3=lca(x,z);
            if (d[x]+d[y]+d[z]-d[t1]-2*d[lca(z,t1)]<ans) ans=d[x]+d[y]+d[z]-d[t1]-2*d[lca(z,t1)],ans2=t1;
            if (d[x]+d[y]+d[z]-d[t2]-2*d[lca(x,t2)]<ans) ans=d[x]+d[y]+d[z]-d[t2]-2*d[lca(x,t2)],ans2=t2;
            if (d[x]+d[y]+d[z]-d[t3]-2*d[lca(y,t3)]<ans) ans=d[x]+d[y]+d[z]-d[t3]-2*d[lca(y,t3)],ans2=t3;
            printf("%d %d
    ",ans2,ans);
        }
        return 0;
    } 
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  • 原文地址:https://www.cnblogs.com/ctlchild/p/5122681.html
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