• ACM-ICPC 2018 焦作赛区网络预赛 I题 Save the Room


    Bob is a sorcerer. He lives in a cuboid room which has a length of AA, a width of BB and a height of CC, so we represent it as AA * BB * CC. One day, he finds that his room is filled with unknown dark energy. Bob wants to neutralize all the dark energy in his room with his light magic. He can summon a 11 * 11 * 22 cuboid at a time to neutralize dark energy. But the cuboid must be totally in dark energy to take effect. Can you foresee whether Bob can save his room or not?

    Input

    Input has TT test cases. T le 100T100

    For each line, there are three integers A, B, CA,B,C.

    1 le A, B, C le 1001A,B,C100

    Output

    For each test case, if Bob can save his room, print"Yes", otherwise print"No".

    样例输入

    1 1 2
    1 1 4
    1 1 1

    样例输出

    Yes
    Yes
    No

    题目来源

    ACM-ICPC 2018 焦作赛区网络预赛

    题解:水题:只要判断a,b,c中是否有一个数被2整除即可;

    参考代码:

     1 #include<bits/stdc++.h>
     2 using namespace std;
     3 #define mem(a,b) memset(a,b,sizeof a)
     4 #define eps 1e-8
     5 #define PI acos(-1.0)
     6 typedef long long LL;
     7 typedef pair<int,int> P;
     8 const int INF=0x3f3f3f3f;
     9 int a,b,c;
    10 
    11 int main()
    12 {
    13     while(~scanf("%d%d%d",&a,&b,&c))
    14     {
    15         if(a%2==0 || b%2==0 || c%2==0) puts("Yes");
    16         else puts("No");
    17     }    
    18     return 0;
    19 }
    View Code

      

  • 相关阅读:
    cmd命令操作Mysql数据库
    可编程作息时间控制器设计
    博客第一天
    PRML 1: Gaussian Distribution
    KMP String Matching Algorithm
    Reinstall Ubuntu 14.04
    Computability 4: Decidability and R.E. Sets (I)
    Consumer-Producer Problem
    Compile the Linux Kernel
    Introduction to Linux Kernel
  • 原文地址:https://www.cnblogs.com/csushl/p/9651915.html
Copyright © 2020-2023  润新知