Write an algorithm to determine if a number is "happy".
A happy number is a number defined by the following process: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. Those numbers for which this process ends in 1 are happy numbers.
Example: 19 is a happy number
- 12 + 92 = 82
- 82 + 22 = 68
- 62 + 82 = 100
- 12 + 02 + 02 = 1
Credits:
Special thanks to @mithmatt and @ts for adding this problem and creating all test cases.
题目:让你判断一个数是否是开心数。一个正数,用它的数字的平方和来代替他,如果有结果等于1,则就是一个开心数。如果一个数一直无限循环还是得不到1,
那么就不是开心数。
这个题目要建立一个hash表,来判断是否无限循环。
class Solution { public: bool isHappy(int n) { map<int, int> intMap; int sum; while(1) { sum = 0; while (n >= 10) { sum += (n % 10)*(n % 10); n = n / 10; } sum += n*n; if (1 == sum)return true; else n = sum; if (intMap.find(n) == intMap.end()) intMap[n] = 1; else break; } return false; } };