打印1到最大的n位数

#include "stdafx.h"
#include <iostream>
#include <exception>
#include <vector>
#include <stack>
/*
题目:打印1到最大的n位数
     输入数字n,按顺序打印出从1到最大的n位数的十进制数.比如输入3,则打印出1,2,3一直到最大的3位数即999
*/
using namespace std;

bool Increment(char * number)
{
    bool isOverflow = false;
    int nTakeOver = 0;
    int nLength = strlen(number);
    cout<<"strlen(number):"<<nLength<<endl;
    for(int i = nLength -1;i>=0;--i)
    {
        int nSum = number[i]-'0'+nTakeOver;//将第i位的字符改成整形.加上是否有进位.
        if(i==nLength-1)
            nSum++; //往最低位加一个1,如果加上1,大于等于10.就要往前进位.
        if(nSum>=10)
        {
            if(i==0)
                isOverflow = true;
            else
            {
                nSum -=10;
                nTakeOver = 1;
                number[i] = '0' +nSum;
            }
        }
        else
        {
            number[i] = '0' +nSum;
            break;
        }
    }
    return isOverflow;
}
void PrintNumber(char* number)
{
    while(*number=='0')
        number++;
    cout<<number<<endl;
}


int _tmain(int argc, _TCHAR* argv[])
{ 
    int n;
    cin>>n;
    if(n<=0)

    {
        cout<<"n不合适"<<endl;
    }
    else
    {
        char *number = new char[n+1];
        //number[0]='0';
        memset(number,'0',n);
        number[n] = '';
        while(!Increment(number))
        {
            PrintNumber(number);
        }
            delete []number;
    }

    return 0 ;
}