Django学习-10-命名空间

不使用命名空间，且两个APP某条url使用相同的name属性

 

app01_urls.py

urlpatterns = [
    url(r'aaa/$', views.app01_aaa, name="index"),
]

 

app02_urls.py

urlpatterns = [
    url(r'aaa/$', views.app02_aaa, name="index"),
]

各自的函数中同时反解URL

#app01.views
def aaa(request):
    return  HttpResponse(reverse("index"))

#app02.views
def aaa(request):
    return  HttpResponse(reverse("index"))

页面显示结果app01.views

#app01

/app01aaa/


#app02

/app01aaa/

  

 

总结

由于name没有作用域，Django在反解URL时，会在项目全局顺序搜索，当查找到第一个name指定URL时，立即返回

我们在开发项目时，会经常使用name属性反解出URL，当不小心定义相同的name时，可能会导致URL反解错误，为了避免这种事情发生，引入了命名空间

 

 

解决

使用Django提供namespace参数

 

 

 

使用命名空间

 

app.urls必须添加变量

app_name = 'app01'

project_urls.py

from django.conf.urls import url,include

urlpatterns = [
    url(r'^aaa', include("app01.urls"),namespace='aaa')),
    url(r'^bbb', include("app02.urls"),namespace='bbb')),
]

 

app01_urls.py

from django.conf.urls import url
from app01 import views

app_name = "app01"

urlpatterns = [
    url(r'aaa/$', views.aaa, name="index"),
]

 

app02_urls.py

from django.conf.urls import url
from app01 import views

app_name = "app02"

urlpatterns = [
    url(r'aaa/$', views.aaa, name="index"),
]

app01_views.py

def aaa(request):
    return HttpResponse(reverse("app01:index"))

app02_views.py

def aaa(request):
    return HttpResponse(reverse("app02:index"))

验证

#http://127.0.0.1/aaa/aaa/

# 结果：
# /aaaaaa/


#http://127.0.0.1/bbb/aaa/

# 结果：
# /bbbaaa/