A == B ?
Problem Description
Give you two numbers A and B, if A is equal to B, you should print "YES", or print "NO".
Input
each test case contains two numbers A and B.
Output
for each case, if A is equal to B, you should print "YES", or print "NO".
Sample Input
1 22 2
3 3
4 3
Sample Output
NOYES
YES
NO
AC code:
#include <stdio.h>
#include <string.h>
void A(char *s)
{
int len = strlen(s);
char *p = s + len - 1;
if (strchr(s, '.'))
while (*p == '0') *p-- = 0;
if (*p == '.') *p = 0;
}
int main(void)
{
char *pa, *pb;
char a[100024], b[100024];
while (scanf("%s%s", &a, &b) != EOF)
{
pa = a; pb = b;
while (*pa == '0') pa++;
while (*pb == '0') pb++;
A(pa); A(pb);
puts(strcmp(pa, pb) ? "NO" : "YES");
}
return 0;
}
void A(char *s)
{
int len = strlen(s);
char *p = s + len - 1;
if (strchr(s, '.'))
while (*p == '0') *p-- = 0;
if (*p == '.') *p = 0;
}
int main(void)
{
char *pa, *pb;
char a[100024], b[100024];
while (scanf("%s%s", &a, &b) != EOF)
{
pa = a; pb = b;
while (*pa == '0') pa++;
while (*pb == '0') pb++;
A(pa); A(pb);
puts(strcmp(pa, pb) ? "NO" : "YES");
}
return 0;
}