• DQL


    1)基本查询

    语法:select 查询列表 from 表名;
    
    特点:
     1.查询结果是一张虚拟表, 不是真实存在
     2.查询列表,可以是常量、字段名、表达式、函数
        
        
    
    代码
    #语法:select 查询列表 from 表名;
    
    #显示employees中所有字段信息
    select * from employees;
    
    #只显示employees中salary字段
    select salary from employees;
    
    #显示employees中部分字段
    select first_name,last_name,salary,hiredate from employees;
    
    #对查询产生的结果--虚拟表 给字段起别名
    select first_name as 姓氏 ,last_name as 名字,salary as 工资 ,hiredate as 入职时间 
    from employees;
    
    
    select first_name as 姓氏 ,last_name as 名字,salary as 工资 ,hiredate as 入职时间,
    salary+10000 as 涨薪一万后 
    from employees;
    
    select 99;
    
    # 获取当前系统时间 new Date() 
    select now();
    
    

    2)条件查询

    语法:select 查询列表 from 表名 where 条件;
    
    特点:
        1.条件表达式:>  <  >=  <=  =  != <>
        2.逻辑表达式: and  or  not
        3.模糊条件: like  / between...and  /in/ not null
    
    1.条件表达式:
    案例1:查询员工薪资>10000的员工信息
    select * from employees where salary > 10000;
    
    案例2:查询姓氏不是 john 的员工的薪资和姓名
    select salary,first_name,last_name from employees where first_name <> 'John';
    
    2.逻辑表达式
    案例3:查询员工的薪资大于10000并且小于20000的员工姓名和薪资
    select last_name,salary from employees where salary > 10000 and salary < 20000;
    
    案例4:查询员工的薪资不在10000到20000之间的员工信息
    select * from employees where salary < 10000 or salary > 20000;
    select * from employees where salary not between 10000 and 20000;
    
    3.模糊条件
    案例5:查询员工名字中第一个字符是e的员工信息
    select last_name from employees where last_name like 'e%';
    
    案例6:查询员工名字中第二个字符是e第五个字符是a的员工的名字和薪资
    select last_name,salary from employees where last_name like '_e__a%';
    
    案例7:查询员工的姓名中第二个字符是_的员工信息
    
    select * from employees where last_name like '_\_%';
    
    案例8: 查询员工的年薪在10w到20w之间的员工名字和薪资
    
    select last_name as 姓名, salary as 月薪,salary*12 as 年薪
    from employees where salary*12 between 100000 and 200000;
    
    案例9:查询员工的编号为(1,102,104,105,109)的员工信息
    
    select * from employees where employee_id = 1 or employee_id = 102 
    or employee_id = 104 or employee_id = 105 or employee_id = 109;
    
    select * from employees where employee_id in(1,102,104,105,109);
    
    案例10:查询有奖金的员工信息
    select * from employees where commission_pct is null;
    select * from employees where commission_pct is not null;
    

  • 相关阅读:
    Python编程笔记二进制、字符编码、数据类型
    Python之路Python内置函数、zip()、max()、min()
    替换RTXLogo插件说明
    RTX修改标题logo方法
    RTX和谐说明
    RTX数据表分析
    RTX系统整合记录
    HiMall 3接口鉴权参考
    第三方系统接入
    学习记录
  • 原文地址:https://www.cnblogs.com/conglingkaishi/p/15215276.html
Copyright © 2020-2023  润新知