那些 Cynthia 教我的事 之 PMSec (三)

在项目中，聪明的Jenny童鞋提了一个suggestion，即将同一个店同一人提交的请求，经过上级批准之后，邮件内容需要合并。

非常滴合理有木有~~

提交十个申请，将收到十封邮件，的确不友好哦。可是由于中间任何一级supervisor都可以为子店提交request，高level的都可以批准。）

于是，烧脑开始了。。。

（话说别人都不用烧，可怜我二八六的大脑啊。。。）

审批者提交的List如下：

 即：

A 提了2个request 关于store 1  --合并为一封邮件

         1个request 关于store2  -- 单独一封邮件

B 提了1个request 关于store1 -- 单独一封邮件

啊啊啊，Cynthia给我讲完，我还思考了辣么久，%>_<%，勇敢接受自己吧~

1）定义一个简单的Class.

  public  class Mix
    {
      public int StoreId { get; set; }
      public string Requeseter { get; set; }
      public int EmployeeId { set; get; }
    }

2) 赋值

            List<Mix> list = new List<Mix>();
            int i = 1000;
            list.AddRange(new List<Mix> { new Mix { StoreId = 1, Requeseter = "A", EmployeeId = i + 1 }, new Mix { StoreId = 1, Requeseter = "A", EmployeeId = i + 2 }, new Mix { StoreId = 2, Requeseter = "A", EmployeeId = i + 4 }, new Mix { StoreId = 2, Requeseter = "B", EmployeeId = i + 3 } });

3）取出所有无重复的store 和requester

            List<int> store = new List<int>();
            List<string> requester = new List<string>();
            foreach (Mix m in list)
            {
                if (!store.Contains(m.StoreId))
                {
                    store.Add(m.StoreId);
                }
                if (!requester.Contains(m.Requeseter))
                {
                    requester.Add(m.Requeseter);
                }
            }

4) 将相同store的request归入同一List.

            foreach (int st in store)
            {
                listbystore = list.FindAll(z => z.StoreId == st);
                                 ...
             }

5)将分好的list再次按不同requester进行循环，取得store和外循环相等，requester和内循环相等的最终finallist.

                foreach (string re in requester)
                {
                   listbyrequester= listbystore.FindAll(p => p.Requeseter == re);
                   
                  listfinal= listbyrequester.FindAll(p => p.StoreId.CompareTo(st) == 0);           
                 }

6)根据finallist的元素个数进行判断是否需要合并。
   最初，这个地方未做判断，发现输出和输入list竟然一！个！样！

   这个地方代码有点怪哈，O(∩_∩)O哈哈~

                  if (listfinal.Count ==1)
                  {
                      listfinal.ForEach(z => { Console.Write(st); Console.Write(":"); Console.Write(z.Requeseter); });
                  }
                  else if(listfinal.Count>1)
                  {
                     Console.Write( listfinal.Find(z => z.StoreId==st).StoreId);
                     Console.Write(":");
                     Console.Write(listfinal.Find(z => z.StoreId == st).Requeseter);
                     SentEmail.sendGroupEmail(listfinal);

                  }

7）发邮件 大功告成

略草，嘿嘿。

       public static void sendGroupEmail(List<Mix> list)
        {
            StringBuilder sb = new StringBuilder();
            sb.Append("<table border='1'><tr><td>Store</td><td>Employee</td><td>Requester</td></tr>");
            list.ForEach(p => { sb.Append("<tr>").Append("<td>").Append(p.StoreId.ToString()).Append("</td>").Append("<td>").Append(p.EmployeeId).Append("</td>").Append("<td>").Append(p.Requeseter.ToString()).Append("</td>").Append("</tr>"); });
            sb.Append("</table>");
            sent(string.Empty,sb.ToString(),string.Empty,string.Empty);
        }


        static void sent(string subject,string content,string mailTo,string mailcc)
        {
            MailMessage mailObj = new MailMessage();
            mailObj.From = new MailAddress("xxx@163.com"); //发送人邮箱地址
            mailObj.To.Add("1031275749@qq.com");   //收件人邮箱地址
            mailObj.Subject = "subject";    //主题
            //actionrequiredurl = "<a href='" + actionrequiredurl + "'>here</a>";
            mailObj.IsBodyHtml = true;
            mailObj.Body = content;
            ////附件
            //foreach (Attachment a in getAttachmentList())
            //{
            //    mailObj.Attachments.Add(a);
            //}
            SmtpClient smtp = new SmtpClient();
            smtp.Host = "smtp.163.com";         //smtp服务器名称
            smtp.UseDefaultCredentials = true;
            smtp.Credentials = new NetworkCredential("***", "****");  //发送人的登录名和密码
            smtp.Send(mailObj);
        }

8）结果

虽然很草而且想了很久，还是比较有成就感滴。。。

感谢Cynthia，O(∩_∩)O谢谢~

记录下完整代码以备查阅：

    class Program
    {
        static void Main(string[] args)
        {
            List<Mix> list = new List<Mix>();
            List<Mix> listbystore = new List<Mix>();
            List<Mix> listbyrequester = new List<Mix>();
            List<Mix> listfinal = new List<Mix>();

            List<int> store = new List<int>();
            List<string> requester = new List<string>();
            int i = 1000;
            list.AddRange(new List<Mix> { new Mix { StoreId = 1, Requeseter = "A", EmployeeId = i + 1 }, new Mix { StoreId = 1, Requeseter = "A", EmployeeId = i + 2 }, new Mix { StoreId = 2, Requeseter = "A", EmployeeId = i + 4 }, new Mix { StoreId = 2, Requeseter = "B", EmployeeId = i + 3 } });
            //list.ForEach(p => Console.WriteLine(p.StoreId));
            foreach (Mix m in list)
            {
                if (!store.Contains(m.StoreId))
                {
                    store.Add(m.StoreId);
                }
                if (!requester.Contains(m.Requeseter))
                {
                    requester.Add(m.Requeseter);
                }
            }

            foreach (int st in store)
            {
                listbystore = list.FindAll(z => z.StoreId == st);
                //listbystore.ForEach(p => { Console.Write(p.StoreId); Console.Write(":"); Console.Write(p.Requeseter); Console.WriteLine(); });
                //Console.WriteLine();   
                    //1:A
                    //1:A

                    //29:A
                    //29:B
                foreach (string re in requester)
                {
                   listbyrequester= listbystore.FindAll(p => p.Requeseter == re);
                   
                  listfinal= listbyrequester.FindAll(p => p.StoreId.CompareTo(st) == 0);
                  if (listfinal.Count ==1)
                  {
                      listfinal.ForEach(z => { Console.Write(st); Console.Write(":"); Console.Write(z.Requeseter); });
                  }
                  else if(listfinal.Count>1)
                  {
                     Console.Write( listfinal.Find(z => z.StoreId==st).StoreId);
                     Console.Write(":");
                     Console.Write(listfinal.Find(z => z.StoreId == st).Requeseter);
                     SentEmail.sendGroupEmail(listfinal);

                  }
                   Console.WriteLine("----------------");
                }



            }
            Console.ReadKey();
           
        }
    }