[LeetCode] 1184. Distance Between Bus Stops

 

A bus has n stops numbered from 0 to n - 1 that form a circle. We know the distance between all pairs of neighboring stops where distance[i] is the distance between the stops number i and (i + 1) % n.

The bus goes along both directions i.e. clockwise and counterclockwise.

Return the shortest distance between the given start and destination stops.

Example 1:

Input: distance = [1,2,3,4], start = 0, destination = 1
Output: 1
Explanation: Distance between 0 and 1 is 1 or 9, minimum is 1.

Example 2:

Input: distance = [1,2,3,4], start = 0, destination = 2
Output: 3
Explanation: Distance between 0 and 2 is 3 or 7, minimum is 3.

Example 3:

Input: distance = [1,2,3,4], start = 0, destination = 3
Output: 4
Explanation: Distance between 0 and 3 is 6 or 4, minimum is 4.

Constraints:

• 1 <= n <= 10^4
• distance.length == n
• 0 <= start, destination < n
• 0 <= distance[i] <= 10^4

公交站间的距离。

环形公交路线上有 n 个站，按次序从 0 到 n - 1 进行编号。我们已知每一对相邻公交站之间的距离，distance[i] 表示编号为 i 的车站和编号为 (i + 1) % n 的车站之间的距离。

环线上的公交车都可以按顺时针和逆时针的方向行驶。

返回乘客从出发点 start 到目的地 destination 之间的最短距离。 

来源：力扣（LeetCode）
链接：https://leetcode.cn/problems/distance-between-bus-stops
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题目不难，但是做法很巧妙。题目要求计算的是两点之间的最短距离，最短距离的计算有两种方式，一种是顺时针，一种是逆时针。顺时针很好算，逆时针的算法是整圈的距离 - 顺时针的距离。

时间O(n)

空间O(1)

Java实现

class Solution {
    public int distanceBetweenBusStops(int[] distance, int start, int destination) {
        int total = 0;
        for (int dis : distance) {
            total += dis;
        }
        
        if (start > destination) {
            int temp = start;
            start = destination;
            destination = temp;
        }
        int dis1 = 0;
        for (int i = start; i < destination; i++) {
            dis1 += distance[i];
        }
        return Math.min(dis1, total - dis1);
    }
}

LeetCode 题目总结