Given an array of n
integers nums
and an integer target
, find the number of index triplets i
, j
, k
with 0 <= i < j < k < n
that satisfy the condition nums[i] + nums[j] + nums[k] < target
.
Example 1:
Input: nums = [-2,0,1,3], target = 2 Output: 2 Explanation: Because there are two triplets which sums are less than 2: [-2,0,1] [-2,0,3]
Example 2:
Input: nums = [], target = 0 Output: 0
Example 3:
Input: nums = [0], target = 0 Output: 0
Constraints:
n == nums.length
0 <= n <= 3500
-100 <= nums[i] <= 100
-100 <= target <= 100
较小的三数之和。
思路跟 3sum 差不多,但是这个题要找的是有多少种组合能满足三数之和小于 target。思路还是先固定一个数字,然后另两个数字是通过双指针逼近的方式做。
时间O(n^2)
空间O(1)
Java实现
1 class Solution { 2 public int threeSumSmaller(int[] nums, int target) { 3 int res = 0; 4 Arrays.sort(nums); 5 for (int i = 0; i < nums.length - 2; i++) { 6 int left = i + 1; 7 int right = nums.length - 1; 8 while (left < right) { 9 if (nums[i] + nums[left] + nums[right] < target) { 10 res += right - left; 11 left++; 12 } else { 13 right--; 14 } 15 } 16 } 17 return res; 18 } 19 }
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