DZY Loves Physics
DZY loves Physics, and he enjoys calculating density.
Almost everything has density, even a graph. We define the density of a non-directed graph (nodes and edges of the graph have some values) as follows:
Once DZY got a graph G, now he wants to find a connected induced subgraph G' of the graph, such that the density of G' is as large as possible.
An induced subgraph G'(V', E') of a graph G(V, E) is a graph that satisfies:
- ;
- edge if and only if , and edge ;
- the value of an edge in G' is the same as the value of the corresponding edge in G, so as the value of a node.
Help DZY to find the induced subgraph with maximum density. Note that the induced subgraph you choose must be connected.
The first line contains two space-separated integers n (1 ≤ n ≤ 500), . Integer n represents the number of nodes of the graph G, m represents the number of edges.
The second line contains n space-separated integers xi (1 ≤ xi ≤ 106), where xi represents the value of the i-th node. Consider the graph nodes are numbered from 1 to n.
Each of the next m lines contains three space-separated integers ai, bi, ci (1 ≤ ai < bi ≤ n; 1 ≤ ci ≤ 103), denoting an edge between node ai and bi with value ci. The graph won't contain multiple edges.
Output a real number denoting the answer, with an absolute or relative error of at most 10 - 9.
1 0 1
0.000000000000000
2 1 1 2 1 2 1
3.000000000000000
5 6 13 56 73 98 17 1 2 56 1 3 29 1 4 42 2 3 95 2 4 88 3 4 63
2.965517241379311
In the first sample, you can only choose an empty subgraph, or the subgraph containing only node 1.
In the second sample, choosing the whole graph is optimal.
#include <map> #include <set> #include <cstdio> #include <cstring> #include <algorithm> #include <queue> #include <iostream> #include <stack> #include <cmath> #include <string> #include <vector> #include <cstdlib> //#include <bits/stdc++.h> //#define LOACL #define space " " using namespace std; //typedef long long LL; typedef __int64 Int; typedef pair<int, int> paii; const int INF = 0x3f3f3f3f; const double ESP = 1e-5; const double PI = acos(-1.0); const int MOD = 1e9 + 7; const int MAXN = 1e5 + 10; double v[MAXN], e; int main() { int n, m, a, b; while (scanf("%d%d", &n, &m) != EOF) { for (int i = 1; i <= n; i++) { scanf("%lf", &v[i]); } double maxx = 0; for (int i = 0; i < m; i++) { scanf("%d%d%lf", &a, &b, &e); maxx = max(maxx, (v[a]+v[b])/e); } printf("%.10lf ", maxx); } return 0; }