• 栈 ADT


      栈(stack)是插入和删除只能在一个位置上进行的表(后进先出),该位置是表的末端,叫做栈的顶(top)。对栈的基本操作有 push(进栈) 和 pop(出栈),push 相当于插入,pop 相当于删除。

      左图栈模型说明:通过 push 向栈输入,通过 pop 和 top 从栈输出

      右图栈模型说明:栈顶是栈中唯一可见的元素

    • 栈的数组实现

      public class ArrayStack<T> {
      
          //设置为2是为了检验ensureCapacity()方法的正确性
          private Object[] data = new Object[2];
      
          private int size;
      
          //是否空栈
          public boolean empty() {
              return size == 0;
          }
      
          //进栈
          public void push(T t) {
              ensureCapacity();
              data[size++] = t;
          }
      
          //出栈
          public T pop() {
              //noinspection unchecked
              return (T) data[--size];
          }
      
          //确保容量
          private void ensureCapacity() {
              if (size < data.length) {
                  return;
              }
              data = Arrays.copyOf(data, data.length + (data.length >> 1));
          }
      
          public static void main(String[] args) {
              ArrayStack<String> stack = new ArrayStack<>();
              char c[] = "Array Stack".toCharArray();
              for (int i = c.length - 1; i >= 0; i--) {
                  stack.push(String.valueOf(c[i]));
              }
              while (!stack.empty()) {
                  System.out.print(stack.pop());
              }
          }
      
      }
    • 栈的链表实现
      public class LinkedStack<T> {
      
          private Node<T> node;
      
          private int size;
      
          private class Node<T> {
      
              T item;
      
              Node<T> next;
      
              public Node(T item, Node<T> next) {
                  this.item = item;
                  this.next = next;
              }
          }
      
          //是否空栈
          public boolean empty() {
              return size == 0;
          }
      
          //进栈
          public void push(T t) {
              Node<T> n = new Node<>(t, node);
              node = n;
              size++;
          }
      
          //出栈
          public T pop() {
              T t = node.item;
              node = node.next;
              size--;
              return t;
          }
      
          public static void main(String[] args) {
              LinkedStack<String> stack = new LinkedStack<>();
              char c[] = "Linked Stack".toCharArray();
              for (int i = c.length - 1; i >= 0; i--) {
                  stack.push(String.valueOf(c[i]));
              }
              while (!stack.empty()) {
                  System.out.print(stack.pop());
              }
          }
      
      }
       
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  • 原文地址:https://www.cnblogs.com/cmdra/p/5922109.html
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