代码
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<vector<int>> ans;
vector<int> path;
vector<vector<int>> pathSum(TreeNode* root, int sum) {
if (root) dfs(root, sum);
return ans;
}
void dfs(TreeNode* root, int sum) {
path.push_back(root->val);
sum -= root->val;
if (!root->left && !root->right) {
if (!sum) {
ans.push_back(path);
}
} else {
if (root->left) dfs(root->left, sum);
if (root->right) dfs(root->right, sum);
}
path.pop_back();
}
};