代码
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
bool hasPathSum(TreeNode* root, int sum) {
if (!root) return false;
sum -= root->val;
if (!root->left && !root->right) return !sum;
return root->left && hasPathSum(root->left, sum) || root->right && hasPathSum(root->right, sum);
}
};