代码
class Solution {
public:
bool isMatch(string s, string p) {
int n = s.size(), m = p.size();
s = ' ' + s, p = ' ' + p;
vector<vector<bool>> f(n + 1, vector<bool>(m + 1));
f[0][0] = true;
for (int i = 0; i <= n; ++i) {
for (int j = 1; j <= m; ++j) {
if (p[j] == '*') {
f[i][j] = f[i][j - 1] || i && f[i - 1][j];
} else {
f[i][j] = (s[i] == p[j] || p[j] == '?') && i && f[i - 1][j - 1];
}
}
}
return f[n][m];
}
};