最小生成树
Prim
朴素版(O(n^2))和堆优化版(O(mlogn))
#include <iostream>
#include <algorithm>
#include <cstring>
using namespace std;
const int N = 510, INF = 0x3f3f3f3f;
int n, m;
int g[N][N], dist[N];
bool st[N];
int prim() {
int res = 0;
memset(dist, 0x3f, sizeof dist);
for (int i = 0; i < n; ++i) {
int t = -1;
for (int j = 1; j <= n; ++j) {
if (!st[j] && (t == -1 || dist[t] > dist[j])) t = j;
}
if (i && dist[t] == INF) return INF;
if (i) res += dist[t];
st[t] = true;
for (int j = 1; j <= n; ++j) dist[j] = min(dist[j], g[t][j]);
}
return res;
}
int main() {
cin >> n >> m;
memset(g, 0x3f, sizeof g);
while (m--) {
int a, b, c;
cin >> a >> b >> c;
g[a][b] = g[b][a] = min(g[a][b], c);
}
int t = prim();
if (t == INF) puts("impossible");
else cout << t << endl;
return 0;
}
Kruskal
(O(mlogn))
- 将所有边按权重从小到大排序;
- 枚举每条边a、b、w,如果a、b不连通,将这条边加入集合。
#include <iostream>
#include <algorithm>
#include <cstring>
using namespace std;
const int N = 200010;
int n, m;
int p[N];
int find(int x) {
if (p[x] != x) p[x] = find(p[x]);
return p[x];
}
struct edge {
int a, b, w;
bool operator< (const edge &W) const {
return w < W.w;
}
} edges[N];
int main() {
cin >> n >> m;
for (int i = 0; i < m; ++i) {
int a, b, w;
cin >> a >> b >> w;
edges[i] = {a, b, w};
}
sort(edges, edges + m);
for (int i = 1; i <= n; ++i) p[i] = i;
int res = 0, cnt = 0;
for (int i = 0; i < m; ++i) {
int a = edges[i].a, b = edges[i].b, w = edges[i].w;
a = find(a), b = find(b);
if (a != b) {
p[a] = b;
res += w;
cnt++;
}
}
if (cnt < n - 1) puts("impossible");
else cout << res << endl;
return 0;
}