• java学习笔记 (1) —— Strut2.3.24环境搭建


    1、打开MyEclipse,添加WebProject,名称为testStruts2

    2、配置Tomcat环境。

      1) 在窗口——首选项——MyEclipse——Servers下找到Tomcat6.x

      2) 选择Enable、浏览找到本机Tomcat6文件位置

      3) 找到Tomcat——conf——server.xml文件、在</Host>结束标签前添加

    <Context path="/testStruts2" docBase="E:softwareMyEclipseWorkSpaces	estStruts2WebRoot" reloadable="true" />

    3、引入jar包

    4、配置web.xml

    <?xml version="1.0" encoding="UTF-8"?>
    <web-app version="2.4" 
        xmlns="http://java.sun.com/xml/ns/j2ee" 
        xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
        xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee 
        http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
            <filter>
            <filter-name>struts2</filter-name>
                <filter-class>org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter</filter-class>
        </filter>
        <filter-mapping>
            <filter-name>struts2</filter-name>
            <url-pattern>/*</url-pattern>
        </filter-mapping>
    </web-app>
            

    5、在src路径下建立struts.xml

    <?xml version="1.0" encoding="UTF-8" ?>
    
    <!DOCTYPE struts PUBLIC
        "-//Apache Software Foundation//DTD Struts Configuration 2.3//EN"
        "http://struts.apache.org/dtds/struts-2.3.dtd"> 
        
        <struts>
            <package name="testStruts2" extends="struts-default" namespace="">
                <action name="login" class="com.test.action.LoginAction">
                    <result name="success">/result.jsp</result>
                </action>
         </package>
        </struts>

    6、在src路径下建立类文件

    package com.test.action;
    
    import com.opensymphony.xwork2.ActionSupport;
    
    public class LoginAction extends ActionSupport
    {
        private static final long serialVersionUID = -74906200993380354L;
        
        private String username;
        private String password;
        public String getUsername() {
            return username;
        }
        public void setUsername(String username) {
            this.username = username;
        }
        public String getPassword() {
            return password;
        }
        public void setPassword(String password) {
            this.password = password;
        }
        
        public String execute() throws Exception
        {
            return "success";
        }
    }
        

    7、在WebRoot路径下新建login.jsp、result.jsp进行测试

    /**
    * login.jsp
    */
      <form action="login" method="post" > 
          username:<input type="text" name="username"><br>
          password:<input type="text" name="password">
      
      <input type="submit" value="submit">
      </form>
    
    /**
    * result.jsp
    */
        username:${requestScope.username }<br>
        password:${requestScope.password }
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  • 原文地址:https://www.cnblogs.com/cklovefan/p/5236701.html
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