• Bzoj3510:首都


    Sol

    (LCT)动态维护树重心

    方法一

    因为只有加边,所以可以暴力启发式合并,维护重心
    维护子树信息,子树大小不超过一半
    复杂度两只(log)

    方法二

    扣出两个重心的链,链上二分找
    每次(Splay)重心,应该是一只(log)的吧。。。

    # include <bits/stdc++.h>
    # define RG register
    # define IL inline
    # define Fill(a, b) memset(a, b, sizeof(a))
    using namespace std;
    typedef long long ll;
    const int _(1e5 + 5);
    
    IL int Input(){
    	RG int x = 0, z = 1; RG char c = getchar();
    	for(; c < '0' || c > '9'; c = getchar()) z = c == '-' ? -1 : 1;
    	for(; c >= '0' && c <= '9'; c = getchar()) x = (x << 1) + (x << 3) + (c ^ 48);
    	return x * z;
    }
    
    int n, m, Xor, fa[_], ch[2][_], rev[_], S[_], sum[_], val[_], rt[_];
    char op;
    
    IL int Son(RG int x){
    	return ch[1][fa[x]] == x;
    }
    
    IL int Isroot(RG int x){
    	return ch[0][fa[x]] != x && ch[1][fa[x]] != x;
    }
    
    IL void Reverse(RG int x){
    	if(!x) return;
    	rev[x] ^= 1, swap(ch[0][x], ch[1][x]);
    }
    
    IL void Pushdown(RG int x){
    	if(!rev[x]) return;
    	Reverse(ch[0][x]), Reverse(ch[1][x]), rev[x] ^= 1;
    }
    
    IL void Update(RG int x){
    	sum[x] = sum[ch[0][x]] + sum[ch[1][x]] + val[x] + 1;
    }
    
    IL void Rotate(RG int x){
    	RG int y = fa[x], z = fa[y], c = Son(x);
    	if(!Isroot(y)) ch[Son(y)][z] = x; fa[x] = z;
    	ch[c][y] = ch[!c][x], fa[ch[c][y]] = y;
    	ch[!c][x] = y, fa[y] = x, Update(y);
    }
    
    IL void Splay(RG int x){
    	S[S[0] = 1] = x;
    	for(RG int y = x; !Isroot(y); y = fa[y]) S[++S[0]] = fa[y];
    	while(S[0]) Pushdown(S[S[0]--]);
    	for(RG int y = fa[x]; !Isroot(x); Rotate(x), y = fa[x])
    		if(!Isroot(y)) Son(x) ^ Son(y) ? Rotate(x) : Rotate(y);
    	Update(x);
    }
    
    IL void Access(RG int x){
    	for(RG int y = 0; x; y = x, x = fa[x]){
    		Splay(x), val[x] += sum[ch[1][x]] - sum[y];
    		ch[1][x] = y, Update(x);
    	}
    }
    
    IL void Makeroot(RG int x){
    	Access(x), Splay(x), Reverse(x);
    }
    
    IL void Split(RG int x, RG int y){
    	Makeroot(x), Access(y), Splay(y);
    }
    
    IL void Adjust(RG int x, RG int y){
    	Split(x, y);
    	RG int flg = 0, t = y, g = 0, size = sum[y] >> 1, sl = 0, sr = 0;
    	while(t){
    		Pushdown(t);
    		RG int ls = ch[0][t], rs = ch[1][t], ssl = sum[ls] + sl, ssr = sum[rs] + sr;
    		if(ssl <= size && ssr <= size){
    			if(!flg || t < g) g = t, flg = 1; 
    			if(ssl == ssr) break;
    		}
    		if(ssr > ssl) sl += sum[ls] + val[t] + 1, t = rs;
    		else sr += sum[rs] + val[t] + 1, t = ls;
    	}
    	Splay(g);
    	Xor ^= x ^ y ^ g, rt[x] = rt[y] = rt[g] = g;
    }
    
    IL int Findrt(RG int x){
    	return x == rt[x] ? x : rt[x] = Findrt(rt[x]);
    }
    
    IL void Link(RG int x, RG int y){
    	Makeroot(x), Makeroot(y);
    	fa[x] = y, val[y] += sum[x], Update(y);
    	Adjust(Findrt(x), Findrt(y));
    }
    
    int main(RG int argc, RG char *argv[]){
    	n = Input(), m = Input();
    	for(RG int i = 1; i <= n; ++i) rt[i] = i, Xor ^= i, sum[i] = 1;
    	for(RG int i = 1, x, y; i <= m; ++i){
    		scanf(" %c", &op);
    		if(op == 'A') x = Input(), y = Input(), Link(x, y);
    		else if(op == 'Q') x = Input(), printf("%d
    ", Findrt(x));
    		else scanf(" %*s"), printf("%d
    ", Xor);
    	}
    	return 0;
    }
    
    
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  • 原文地址:https://www.cnblogs.com/cjoieryl/p/8638798.html
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