• BZOJ1001 狼抓兔子


    最小割

    代码

    # include <bits/stdc++.h>
    # define IL inline
    # define RG register
    # define Fill(a, b) memset(a, b, sizeof(a))
    # define Copy(a, b) memcpy(a, b, sizeof(a))
    using namespace std;
    typedef long long ll;
    const int _(1e6 + 10), __(1e7 + 10);
    
    IL ll Read(){
        RG char c = getchar(); RG ll x = 0, z = 1;
        for(; c < '0' || c > '9'; c = getchar()) z = c == '-' ? -1 : 1;
        for(; c >= '0' && c <= '9'; c = getchar()) x = (x << 1) + (x << 3) + (c ^ 48);
        return x * z;
    }
    
    int n, m, fst[_], nxt[__], to[__], cnt, S, T, lev[_], Q[_], max_flow, w[__];
    int nn[1010][1010], tt;
    
    IL void Add(RG int u, RG int v, RG int f){
        w[cnt] = f; to[cnt] = v; nxt[cnt] = fst[u]; fst[u] = cnt++;
        //w[cnt] = 0; to[cnt] = u; nxt[cnt] = fst[v]; fst[v] = cnt++;
    }
    
    int Dfs(RG int u, RG int maxf){
        if(u == T) return maxf;
        RG int ret = 0;
        for(RG int e = fst[u]; e != -1; e = nxt[e]){
            if(lev[to[e]] != lev[u] + 1 || !w[e]) continue;
            RG int f = Dfs(to[e], min(w[e], maxf - ret));
            ret += f; w[e ^ 1] += f; w[e] -= f;
            if(ret == maxf) break;
        }
        if(!ret) lev[u] = 0;
        return ret;
    }
    
    IL bool Bfs(){
        RG int h, t = 1; Q[h = 0] = S; Fill(lev, 0); lev[S] = 1;
        while(h < t){
            RG int u = Q[h++];
            for(RG int e = fst[u]; e != -1; e = nxt[e]){
                if(lev[to[e]] || !w[e]) continue;
                lev[to[e]] = lev[u] + 1;
                Q[t++] = to[e];
            }
        }
        return lev[T];
    }
    
    int main(){
        n = Read(); m = Read();
        for(RG int i = 1; i <= n; ++i)
            for(RG int j = 1; j <= m; ++j)
              nn[i][j] = ++tt, fst[nn[i][j]] = -1;
        S = 1; T = n * m; RG int a;
        for(RG int i = 1; i <= n; ++i)
            for(RG int j = 1; j < m; ++j)
                a = Read(), Add(nn[i][j], nn[i][j + 1], a), Add(nn[i][j + 1], nn[i][j], a);
        for(RG int i = 1; i < n; ++i)
            for(RG int j = 1; j <= m; ++j)
                a = Read(), Add(nn[i][j], nn[i + 1][j], a), Add(nn[i + 1][j], nn[i][j], a);
        for(RG int i = 1; i < n; ++i)
            for(RG int j = 1; j < m; ++j)
                a = Read(), Add(nn[i][j], nn[i + 1][j + 1], a), Add(nn[i + 1][j + 1], nn[i][j], a);
        while(Bfs()) max_flow += Dfs(S, 0x7fffffff);
        printf("%d
    ", max_flow);
        return 0;
    }
    
    
  • 相关阅读:
    HTML导航
    html5学习笔记
    crm使用soap启用和停用记录
    crmjs区分窗口是否是高速编辑(2)
    关于strace的一点东西
    Android studio第一次使用配置(三)gradle项目构建
    IntelliJ IDEA 问题总结之二(待补充) —— 快捷键、主题样式、导出jar、sqlite
    spark之map与flatMap差别
    leetcode:String to Integer (atoi)
    oracle索引的操作
  • 原文地址:https://www.cnblogs.com/cjoieryl/p/8206355.html
Copyright © 2020-2023  润新知