• 结对编程——四则运算


    一、问题描述:

         某公司程序员二柱的小孩上了小学二年级,老师让家长每天出100道(100以内)四则运算题目给小学生做。

    二、结对对象:周芳 

         博客地址:http://home.cnblogs.com/u/tiffanybear/

         双方贡献:1:1

         结对编程照片:

         

    三、采用语言:java(代码实现如下)

     1 package four_calculate;
     2 
     3 public class Calculate {
     4 
     5     public String randomNum() {
     6         int dividend = (int) (Math.random() * 10);// 随机生成被除数
     7         int divisor = (int) (Math.random() * 10);// 随机生成除数
     8         if (dividend >= divisor) {
     9             int temp = dividend;
    10             dividend = divisor;
    11             divisor = temp;
    12         }
    13         return ("(" + dividend + "/" + divisor + ")");
    14     }
    15 
    16     public static void main(String[] args) {
    17         
    18         String divFirstNum = null;
    19         String divSecondNum = null;
    20         
    21         int k;
    22         int count = 100;
    23         Calculate calculate = new Calculate();
    24         for (int n = 1; n <= count; n++) {
    25             
    26             divFirstNum = calculate.randomNum();
    27             divSecondNum = calculate.randomNum();
    28             
    29             int first = (int) (Math.random() * 100);//算术表达式中的第一个数
    30             int second = (int) (Math.random() * 100);//算术表达式中的第二个数
    31             
    32             switch ((int) (Math.random() * 4)) {
    33             
    34             case 0:
    35                 k = (int) (Math.random() * 3);
    36                 if (k == 0)
    37                     System.out.println(n +": "+ first + "+" + second + "=");
    38                 else if (k == 1)
    39                     System.out.println(n +": "+divFirstNum + "+" + second + "=");
    40                 else if (k == 2)
    41                     System.out.println(n +": "+divSecondNum + "+" + divFirstNum + "=");
    42                 break;
    43             case 1:
    44                 k = (int) (Math.random() * 3);
    45                 if (first < second) {
    46                     int temp = first;
    47                     first= second;
    48                     second = temp;
    49                 }
    50                 if (k == 0)
    51                     System.out.println(n +": "+first + "-" + second + "=");
    52                 else if (k == 1)
    53                     System.out.println(n +": "+second + "-" + divFirstNum + "=");
    54                 else if (k == 2)
    55                     System.out.println(n +": "+divSecondNum + "-" + divFirstNum + "=");
    56                 break;
    57             case 2:
    58                 k = (int) (Math.random() * 3);
    59                 if (k == 0)
    60                     System.out.println(n +": "+first + "*" + second + "=");
    61                 else if (k == 1)
    62                     System.out.println(n +": "+divFirstNum + "*" + second + "=");
    63                 else if (k == 2)
    64                     System.out.println(n +": "+divSecondNum + "*" + divFirstNum + "=");
    65                 break;
    66             case 3:
    67                 while (second == 0)
    68                     second = (int) (Math.random() * 100);
    69                 System.out.println(n +": "+first + "/" + second + "=");
    70                 break;
    71             }
    72         }
    73     }
    74 
    75 }

    四、运行结果截图:

        

    五、心得体会:

         通过这次结对编程,更深刻地体会到了结对编程的好处,也向队友学习到了许多,比如编程的严谨性,思路等。当然,通过结对编程思路也更清晰,出错次数也相对减少!希望以后能经常用这种好的编程方法互相学习!

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  • 原文地址:https://www.cnblogs.com/ciciCassie/p/5376432.html
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