练习题

1
/*the first c programme*/
#include <stdio.h>
main(){
    int num = 1;
    scanf("%d",&num);
    printf("%d",num);
    getch(); 
} 

主要考察输入输出.然后输出结果是:

你输入什么就在屏幕输出什么.

2 

#include "print.h"
int main(void){
      printHello();
      getch();
      return 0;    
}
void printHello(){
         printf("Hello world!
");
}

主要考察函数调用

3 

/*Input 2 numbers output the product*/
#include <stdio.h>
main(){
           int x,y,m;
           printf("Please input x and y
");      
           scanf("%d%d",&x,&y);  
           m=x*y;
           printf("%d * %d = %d
",x,y,m);
           getch();
}    

主要考察函数输入输出

//获取从键盘输入字符

scanf("%d%d",&x,&y);

//打印到屏幕字符

printf("%d * %d = %d ",x,y,m);

4 

/*输入两个浮点数 输出他们中的大数*/
#include <stdio.h>
main(){
     float x,y,c;                /* 变量定义 */
    printf("Please input x and y:
");  /* 提示用户输入数据 */
    scanf("%f%f",&x,&y);
    c=x>y?x:y;              /* 计算c=max(x,y) */
    printf("MAX of (%f,%f) is %f",x,y,c);   /* 输出c */ 
}    

5

6 输出不同类形状所占字节数

#include <stdio.h>
void main(){
    printf("The bytes of the variables are:
");
    printf("int:%d bytes
",sizeof(int));
    /* char型的字节数为1 */
    printf("char:%d byte
",sizeof(char));
    /* short型的字节数为2 */
    printf("short:%d bytes
",sizeof(short));
    /* long型的字节数为4 */
    printf("long:%d bytes
",sizeof(long));
    /* float型的字节数为4 */
    printf("float:%d bytes
",sizeof(float));
    /* double型的字节数为8 */
    printf("double:%d bytes
",sizeof(double));
    /* long double型的字节数为8或10或12 */
    printf("long double:%d bytes
",sizeof(long double));
    getchar();
}

sizeof(number type);

 7 

/* */
#include <stdio.h>
main()
{
    int a=5,b,c,i=10;
    b=a++;
    c=++b;

    printf("a = %d, b = %d, c = %d
",a,b,c);
    printf("i,i++,i++ = %d,%d,%d
",i,i++,i++);
    printf("%d
",++i);
    printf("%d
",--i);
    printf("%d
",i++);
    printf("%d
",i--);
    printf("%d
",-i++);
    printf("%d
",-i--);
    getchar();
}

8 

#include <stdio.h>
main (){
     int i,j,n;
     long sum=0,temp=0;      
     printf("Please input a number to n:
");
     scanf("%d",&n);
     if(n<1){
            printf("the n must no less than 1!
");  
            return;
     }
     for(i=1;i<=n;i++){
         temp  = 0;
         for(j=1;j<=i;j++){
                 temp += j;
         }
          sum+=temp;
     }
     printf("The sum of the sequence(%d) is %d
",n,sum);
    getchar();
    getchar();
}        

10 010 猜数字游戏