问题描述:
You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.
You may assume the two numbers do not contain any leading zero, except the number 0 itself.
Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8
代码:
/** * Definition for singly-linked list. * struct ListNode { * int val; * struct ListNode *next; * }; */ struct ListNode* addTwoNumbers(struct ListNode* l1, struct ListNode* l2) { struct ListNode* res, *L1=l1, *L2=l2, *temp; while (L1&&L2) { L1->val=L2->val=L1->val+L2->val; L1 = L1->next; L2 = L2->next; } res = (L1) ? l1 : l2; temp=res; while (temp) { if (temp->val>=10) { if (!temp->next) temp->next = (struct ListNode*)calloc(1,sizeof(struct ListNode)); temp->val-=10; temp->next->val+=1; } temp = temp->next; } return res; }