• [LeetCode] Interleaving String


    Given s1s2s3, find whether s3 is formed by the interleaving of s1 and s2.

    For example,
    Given:
    s1 = "aabcc",
    s2 = "dbbca",

    When s3 = "aadbbcbcac", return true.
    When s3 = "aadbbbaccc", return false.

    DP.

     1 class Solution {
     2 private:
     3     bool f[1000][1000];
     4 public:
     5     bool isInterleave(string s1, string s2, string s3) {
     6         // Start typing your C/C++ solution below
     7         // DO NOT write int main() function 
     8         if (s1.size() + s2.size() != s3.size())
     9             return false;
    10             
    11         f[0][0] = true;
    12         for(int i = 1; i <= s1.size(); i++)
    13             f[i][0] = f[i-1][0] && (s3[i-1] == s1[i-1]);
    14             
    15         for(int j = 1; j <= s2.size(); j++)
    16             f[0][j] = f[0][j-1] && (s3[j-1] == s2[j-1]);
    17             
    18         for(int i = 1; i <= s1.size(); i++)
    19             for(int j = 1; j <= s2.size(); j++)
    20                 f[i][j] = (f[i][j-1] && s2[j-1] == s3[i+j-1]) || (f[i-1][j] && s1[i-1] == s3[i+j-1]);
    21                 
    22         return f[s1.size()][s2.size()];
    23     }
    24 };
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  • 原文地址:https://www.cnblogs.com/chkkch/p/2787297.html
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