回文数

 1 public boolean isPalindrome(int number) {
 2         int s=number;
 3         if(number<0 || (number%10==0 && number!=0)){
 4             return false;
 5         }
 6         int re=0;
 7         while(number>0){
 8             re=re*10+number%10;
 9             number/=10;
10         }
11         return re==s;
12     }

用时:131ms
时间：2018年11月29日22:39:59
作者：冰樱梦

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原文地址：https://www.cnblogs.com/cherrydream/p/10041477.html