2019.12.17基佬出的一道题

代码如下：

# -*- coding: utf-8 -*-
"""
@File:hz.py    
@E-mail:chenshengkai@vip.qq.com
@Time:2019-12-17 10:28 
@Author:Nobita   
@Version:1.0   
@Desciption:None
"""

from datetime import datetime

'''
题目：
一个数据集合,存有多个这种字典{"time":"2019-04-16 08:23:40"}
对同一天时间的筛选出最早的一条,就是每天只有一条数据，
如果出现多条/就取当天最早的,筛选完后对数据从小到大排序,
数据自己伪造。
'''
dict_data = {
    "time1": "2019-04-01 06:22:41",
    "time2": "2019-04-01 06:22:41",
    "time3": "2019-04-01 09:23:40",
    "time4": "2019-04-01 08:24:45",
    "time5": "2019-04-02 08:23:40",
    "time6": "2019-04-02 13:25:41",
    "time7": "2019-04-03 08:23:40",
    "time8": "2019-04-03 08:23:40",
    "time9": "2019-04-04 08:23:40",
    "time10": "2019-04-05 05:21:41",
    "time11": "2019-04-05 11:23:40",
    "time12": "2019-04-05 09:15:15",
    "time13": "2019-04-06 08:12:12",
    "time14": "2019-04-07 08:57:41",
    "time15": "2019-04-11 09:21:11",
    "time16": "2019-04-12 08:23:40"
}

if __name__ == '__main__':
    dict_list = dict()
    # 循环获取字符串，并进行初步的日期处理
    for v in dict_data.values():
        data = datetime.strptime(v, '%Y-%m-%d %H:%M:%S')
        data_str = str(data.date())
        if data_str not in dict_list:
            dict_list[data_str] = list()
        dict_list[data_str].append(v)
        dict_list[data_str].sort(reverse=False)
    # 获取每个日期第一个并排序
    result = [v[0] for v in dict_list.values()]
    result.sort(reverse=False)
    print(result)