You are given the heads of two sorted linked lists list1 and list2.
Merge the two lists in a one sorted list. The list should be made by splicing together the nodes of the first two lists.
Return the head of the merged linked list.
Input: list1 = [1,2,4], list2 = [1,3,4]
Output: [1,1,2,3,4,4]
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode() {}
* ListNode(int val) { this.val = val; }
* ListNode(int val, ListNode next) { this.val = val; this.next = next; }
* }
*/
class Solution {
/* apply the two-pointer technique */
// public ListNode mergeTwoLists(ListNode list1, ListNode list2) {
// if(list1 == null) return list2;
// if(list2 == null) return list1;
// ListNode resultNode = new ListNode();
// ListNode p = resultNode;
// while(list1 != null && list2 != null){
// if(list1.val < list2.val){
// p.next = list1;
// list1 = list1.next;
// }else{
// p.next = list2;
// list2 = list2.next;
// }
// p = p.next;
// }
// if(list1 != null){
// p.next = list1;
// }
// if(list2 != null){
// p.next = list2;
// }
// return resultNode.next;
// }
/* apply the recursion technique */
public ListNode mergeTwoLists(ListNode list1, ListNode list2) {
if(list1 == null) return list2;
if(list2 == null) return list1;
if(list1.val < list2.val){
list1.next = mergeTwoLists(list1.next, list2);
return list1;
}
list2.next = mergeTwoLists(list1, list2.next);
return list2;
}
}
来源:力扣(LeetCode)
链接:https://leetcode.cn/problems/merge-two-sorted-lists