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    #include <iostream>
    #include <vector>
    #include <cstdio>
    #include <algorithm>
    
    using namespace std;
    #define N 1001000
    
    struct node {
        int b,d;
        double rate;
    }g[N];
    
    double dp[1001000];
    
    int cmp(node n1, node n2) {
        return n1.b < n2.b;
    }
    
    /*请完成下面这个函数,实现题目要求的功能*/
    /*当然,你也可以不按照下面这个模板来作答,完全按照自己的想法来 ^-^ */
    /******************************开始写代码******************************/
    double StockGod(int n, int m, double p, const vector<vector<double>>& prices)
    {
        if (m == 1) {
            return 1;
        }
        int cnt = 0;
        
        for (int i = 0; i < n; i++) {
            
            int b = -1, d = -1;
            int j = 0;
            while (j < m - 1) {
                while (j + 1 < m && prices[j][i] >= prices[j + 1][i]) {
                    j++;
                }
                b = j;
                while (j + 1 < m && prices[j][i] <= prices[j + 1][i]) {
                    j++;
                }
                d = j;
                for (int ii = b;ii < d; ii++) {
                    for (int jj = ii + 1;jj<=d;jj++) {
                        int tb = ii;
                        int td = jj;
                        double dis = prices[td][i] - prices[tb][j];
                        if (dis > 0) {
                            double mm = prices[td][i] * (1 - p) / prices[tb][i];
                            if (mm > 1) {
                                node nn;
                                nn.b = tb;
                                nn.d = td;
                                nn.rate = mm;
                                g[cnt++] = nn;
                            }
                        }
                    }
                }
            }
        }
        
        sort(g, g + cnt, cmp);
        dp[0] = 1;
        double mx = 1;
        int ti = 0;
        for (int i = 0; i < m;i ++) {
            mx = max(dp[i], mx);
            while (ti < cnt && i == g[ti].b) {
                int d= g[ti].d;
                dp[d] = max(dp[d], mx * g[ti].rate);
                ti++;
            }
        }
        
        return mx;
    }
    /******************************结束写代码******************************/
    
    
    int main()
    {
        int n = 0;
        int m = 0;
        double p = 0;
        cin >> n >> m >> p;
        
        vector<vector<double>> prices;
        for(int i = 0; i < m; ++i) {
            prices.push_back(vector<double>());
            for(int j = 0; j < n; ++j) {
                double x = 0;
                cin >> x;
                prices.back().push_back(x);
            }
        }
        
        double final = StockGod(n, m, p, prices);
        printf("%.1f
    ", final);
        
        return 0;
    }
    
    /**
     
    **/
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  • 原文地址:https://www.cnblogs.com/chenhuan001/p/6770719.html
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