• 双向循环链表(DoubleLoopLinkList)


    双向循环链表

    在这里插入图片描述

    关于双向循环链表可以先阅读这篇文章这里就不再赘述:双向链表(DoubleLinkList)

    Node

    template<typename T>
    class Node {
    public:
        T e;
        Node *prev;
        Node *next;
    
        Node() : e(0), prev(nullptr), next(nullptr) {}
    
        Node(const T &E) : e(E), prev(nullptr), next(nullptr) {}
    
        Node(const T &E, Node<T> *Prev, Node<T> *Next) : e(E), prev(Prev), next(Next) {}
    };
    

    构造函数

    DoubleLoopLinkList() : size(0) {
    	//看图得:前驱后继都指向虚拟头节点
    	dummyHead = new Node<T>(0, dummyHead, dummyHead);
    }
    

    添加

    头添加

        void addFirst(const T &e) {
            dummyHead->next = new Node<T>(e, dummyHead, dummyHead->next);
            dummyHead->next->next->prev = dummyHead->next;
            ++size;
        }
    

    指定节点添加

    void add(const int index, const T &e) {
    	assert(index >= 0 && index <= size);
    	Node<T> *prevNode = dummyHead;
    	for (int i = 0; i < index; ++i) {
    	    prevNode = prevNode->next;
    	}
    	prevNode->next = new Node<T>(e, prevNode, prevNode->next);
    	prevNode->next->next->prev = prevNode->prev;
    	++size;
    }
    
    

    尾添加

    
    void addLast(const T &e) {
        dummyHead->prev = new Node<T>(e, dummyHead->prev, dummyHead);
        dummyHead->prev->prev->next = dummyHead->prev;
        ++size;
    }
    

    删除

    头删除

    T removeFirst() {
        remove(0);
    }
    

    指定节点删除

    T remove(int index) {
    	assert(index >= 0 && index < size);
    	Node<T> *prevNode = dummyHead;
    	for (int i = 0; i < index; ++i) {
    	    prevNode = prevNode->next;
    	}
    	Node<T> *retNode = prevNode->next;
    	prevNode->next = retNode->next;
    	retNode->next->prev = retNode->prev;
    	retNode->next = nullptr;
    	retNode->prev = nullptr;
    	--size;
    	T temp = retNode->e;
    	delete retNode;
    	retNode = nullptr;
    	return temp;
    }
    

    尾删除

    T removeLast() {
    	Node<T> *retNode = dummyHead->prev;
    	T temp = retNode->e;
    	dummyHead->prev = retNode->prev;
    	retNode->prev->next = dummyHead;
    	retNode->next = nullptr;
    	retNode->prev = nullptr;
    	delete retNode;
    	retNode = nullptr;
    	--size;
    	return temp;
    }
    

    Code

    //
    // Created by cheng on 2021/7/5.
    //
    
    #ifndef LINKEDLIST_DOUBLELOOPLINKLIST_H
    #define LINKEDLIST_DOUBLELOOPLINKLIST_H
    
    #include <assert.h>
    
    template<typename T>
    class Node {
    public:
        T e;
        Node *prev;
        Node *next;
    
        Node() : e(0), prev(nullptr), next(nullptr) {}
    
        Node(const T &E) : e(E), prev(nullptr), next(nullptr) {}
    
        Node(const T &E, Node<T> *Prev, Node<T> *Next) : e(E), prev(Prev), next(Next) {}
    };
    
    template<typename T>
    class DoubleLoopLinkList {
    public:
        DoubleLoopLinkList() : size(0) {
            dummyHead = new Node<T>(0, dummyHead, dummyHead);
        }
    
        constexpr int getSize() const {
            return size;
        }
    
        constexpr bool isEmpty() const {
            return size == 0;
        }
    
        void add(const int index, const T &e) {
            assert(index >= 0 && index <= size);
            Node<T> *prevNode = dummyHead;
            for (int i = 0; i < index; ++i) {
                prevNode = prevNode->next;
            }
            prevNode->next = new Node<T>(e, prevNode, prevNode->next);
            prevNode->next->next->prev = prevNode->prev;
            ++size;
        }
    
        void addFirst(const T &e) {
            dummyHead->next = new Node<T>(e, dummyHead, dummyHead->next);
            dummyHead->next->next->prev = dummyHead->next;
            ++size;
        }
    
        void addLast(const T &e) {
            dummyHead->prev = new Node<T>(e, dummyHead->prev, dummyHead);
            dummyHead->prev->prev->next = dummyHead->prev;
            ++size;
        }
    
        void set(const int index, const T &e) {
            assert(index >= 0 && index < size);
            Node<T> *cur = dummyHead->next;
            for (int i = 0; i < index; ++i) {
                cur = cur->next;
            }
            cur->e = e;
        }
    
        void setFirst(const T &e) {
            assert(!isEmpty());
            dummyHead->next->e = e;
        }
    
        void setLast(const T &e) {
            assert(!isEmpty());
            dummyHead->prev->e = e;
        }
    
        bool contains(const T &e) const {
            Node<T> *cur = dummyHead->next;
            while (cur != dummyHead) {
                if (cur->e = e) {
                    return true;
                }
                cur = cur->next;
            }
            return false;
        }
    
        T get(const int index) const {
            assert(index >= 0 && index < size);
            Node<T> *cur = dummyHead->next;
            for (int i = 0; i < index; ++i) {
                cur = cur->next;
            }
            return cur->e;
        }
    
        T getFirst() const {
            assert(!isEmpty());
            return dummyHead->next->e;
        }
    
        T getLast() const {
            assert(!isEmpty());
            return dummyHead->prev->e;
        }
    
        T remove(int index) {
            assert(index >= 0 && index < size);
            Node<T> *prevNode = dummyHead;
            for (int i = 0; i < index; ++i) {
                prevNode = prevNode->next;
            }
            Node<T> *retNode = prevNode->next;
            prevNode->next = retNode->next;
            retNode->next->prev = retNode->prev;
            retNode->next = nullptr;
            retNode->prev = nullptr;
            --size;
            T temp = retNode->e;
            delete retNode;
            retNode = nullptr;
            return temp;
        }
    
        T removeFirst() {
            remove(0);
        }
    
        T removeLast() {
            Node<T> *retNode = dummyHead->prev;
            T temp = retNode->e;
            dummyHead->prev = retNode->prev;
            retNode->prev->next = dummyHead;
            retNode->next = nullptr;
            retNode->prev = nullptr;
            delete retNode;
            retNode = nullptr;
            --size;
            return temp;
        }
    
        ~DoubleLoopLinkList() {
            Node<T> *cur = dummyHead->next;
            Node<T> *temp;
            while (cur != nullptr) {
                temp = cur->next;
                delete cur;
                cur = temp;
            }
            dummyHead->next = nullptr;
            dummyHead->prev = nullptr;
            delete dummyHead;
            dummyHead = nullptr;
        }
    
        void print() {
            Node<T> *prev = dummyHead;
            std::cout << "LinkedList: size = " << size << std::endl;
            std::cout << "[";
            for (int i = 0; i < size; ++i) {
                prev = prev->next;
                std::cout << prev->e;
                if (i < size - 1) {
                    std::cout << ", ";
                }
            }
            std::cout << "]" << std::endl;
        }
    
    private:
        Node<T> *dummyHead;
        int size;
    };
    
    #endif //LINKEDLIST_DOUBLELOOPLINKLIST_H
    
    
  • 相关阅读:
    hdu 1427 速算24点 dfs暴力搜索
    hihocoder 九十八周 搜索一 24点
    codeforces 352 div 2 C.Recycling Bottles 贪心
    华中农业大学预赛 B Handing Out Candies 余数的和
    neu 1694 Primorial vs LCM 数论
    Codeforces Round #281 (Div. 2) A. Vasya and Football 暴力
    HDU 5538/ 2015长春区域 L.House Building 水题
    HDU 5536/ 2015长春区域 J.Chip Factory Trie
    HDU 5534/ 2015长春区域H.Partial Tree DP
    HDU 5533/ 2015长春区域 G.Dancing Stars on Me 暴力
  • 原文地址:https://www.cnblogs.com/chengmf/p/14977689.html
Copyright © 2020-2023  润新知