前戏
#元祖:元素不可被改变,不能白增加或者删除 #tuple #tu = (11,22,33,44) #tu.count(22),获取指定元素在元祖中出现的次数 #tu.index(22),获取元素的下标
• 不能增加或者删除元素
1、书写格式
tu = (111,"alex",(11,22),[(33,44)],True,33,44,) print(tu) 结果: (111, 'alex', (11, 22), [(33, 44)], True, 33, 44) # 一般写元组的时候,推荐在最后加入 , # 元素不可被修改,不能被增加或者删除
2、索引
tu = (111,"alex",(11,22),[(33,44)],True,33,44,) print(tu[1]) 结果: alex
3、切片
tu = (111,"alex",(11,22),[(33,44)],True,33,44,) print(tu[1:3]) 结果: ('alex', (11, 22)) #>=1 <3
4、可以被for循环,可迭代对象
tu = (111,"alex",(11,22),[(33,44)],True,33,44,) for i in tu: print(i) 结果: 111 alex (11, 22) [(33, 44)] True 33 44
5、转换
s = "charon" li = ["charon","pluto"] tu = ("pluto","charon",) v = tuple(s) print(v) v1 = tuple(li) print(v1) v2 = list(tu) print(v2) v3 = "_".join(tu) print(v3) li.extend((11,22,33,)) print(li) v4 = li.pop() print(v4) 结果: ('c', 'h', 'a', 'r', 'o', 'n') ('charon', 'pluto') ['pluto', 'charon'] pluto_charon ['charon', 'pluto', 11, 22, 33] 33
6、元祖的一级元素不可修改,删除,增加
tu = (111,"alex",(11,22),[(33,44)],True,33,44,) v = tu[3][0] print(v) tu[3][0] = 2 print(tu) 结果: (33, 44) (111, 'alex', (11, 22), [2], True, 33, 44) #元祖不可以更改,但是元祖里面的列表是可以更改的