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<script type="text/javascript">
//公园里有一堆桃子，猴子每天吃掉一半，挑出一个坏的扔掉，第6天的时候发现还剩1个桃子，问原来有多少个桃子
//函数功能 返回第n天的桃子数量
//递归就是函数自己调自己
var sl;
function ShuLiang(n)
{
if(n==6)
{
sl = 1;
}
else
{
//求当天的数量
//当天的数量 = （下一天的数量+1）*2；
sl = (ShuLiang(n+1)+1)*2;
}
return sl;
}
alert(ShuLiang(1)); //输出(ShuLiang(0)) 结果就是190 当天的数量
//输出(ShuLiang(1)) 结果就是94 下一天的数量
/*
ShuLiang(0) ShuLiang(0)就是sl = (94+1)*2 = 190;
{
sl = (ShuLiang(1)+1)*2; 卡主 sl = (94+1)*2
}
ShuLiang(1)
{
sl = (ShuLiang(2)+1)*2; 卡主 sl = (46+1)*2
}
ShuLiang(2)
{
sl = (ShuLiang(3)+1)*2; 卡主 sl = (22+1)*2;
}
ShuLiang(3)
{
sl = (ShuLiang(4)+1)*2; 卡主 sl = (10+1)*2;
}
ShuLiang(4)
{
sl = (ShuLiang(5)+1)*2; 卡主 sl = (4+1)*2;
}
ShuLiang(5)
{
sl = (ShuLiang(5)+1)*2; 卡主 sl = (1+1)*2;
}
ShuLiang(6)
{
return 1; 发现n=6了就返回sl=1 然后往回计算
}
*/
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