作业1
1．业务接口
1 package lianxi4; 2 3 public interface Business { 4 double RATIO=0.022; 5 double TAX=0.03; 6 void buying (double price); 7 }
2．购房者类
1 package lianxi4; 2 3 public class Buyer implements Business{ 4 String name;//表示购房者姓名 5 public Buyer(String name) { 6 this.name=name; 7 } 8 public void buying (double price){ //显示输出购买一套标价为price元的住宅 9 System.out.println(name+"购买了一套总价为"+price+"元的住宅"); 10 } 11 }
3．中介类
1 package lianxi4; 2 3 public class Intermediary implements Business{ 4 Buyer buyer; 5 Intermediary(Buyer buyer) //构造方法 6 { 7 this.buyer=buyer; 8 9 } 10 public void buying (double price){ 11 buyer.buying(price); 12 this.charing(price); 13 } 14 public void charing(double price){ 15 System.out.println("中介费为"+price*RATIO); 16 System.out.println("契税为"+price*TAX); 17 } 18 19 }
4．Test类
package lianxi4; import java.util.Scanner; public class Test { public static void main(String[] args) { Buyer buyer =new Buyer("Lisa"); Intermediary intermediary = new Intermediary(buyer); Scanner reader = new Scanner(System.in); System.out.println("请输入要购买房屋的标价："); double price = reader.nextDouble(); intermediary.buying(price); } }
运行结果
作业2
题目简述
输入5个数，代表学生成绩，计算其平均成绩。当输入值为负数或大于100时，通过自定义异常处理进行提示。
1.异常类
1 package lianxi3; 2 3 public class MyException extends Exception{ 4 5 public String myMessm(){ 6 7 8 return "成绩不能小于零或大于100,请重新输入！"; 9 } 10 }
2.计算类
1 package lianxi3; 2 3 import java.util.Scanner; 4 5 public class Jisuan { 6 7 public int i; 8 9 public void jisuan(){ 10 Scanner reader = new Scanner(System.in); 11 System.out.println("请输入5个成绩"); 12 int sum=0; 13 for(i=0;i<=4;i++){ 14 int a=reader.nextInt(); 15 try { 16 if(a<0||a>100) 17 throw new MyException(); 18 sum=sum+a; 19 20 } catch (Exception e) { 21 System.out.println(((MyException) e).myMessm()); 22 } 23 if(a<0||a>100) 24 i--; 25 } 26 27 int ave=sum/5; 28 System.out.println("平均成绩是："+ave); 29 30 } 31 }
3.主类
1 package lianxi3; 2 3 public class Example { 4 5 public static void main(String[] args) { 6 Jisuan s1 =new Jisuan(); 7 s1.jisuan(); 8 9 } 10 }
运行结果
