基于xml配置springmvc

controller关键代码

public class MenuController extends MultiActionController

方法：

public ModelAndView list(HttpServletRequest request,
          HttpServletResponse response)
	{
	  CoreMenuQuery query = new CoreMenuQuery();
	  List<CoreMenu> list = coreMenuService.find(query);
		return new ModelAndView("index");  
	}

一定要

HttpServletRequest request,
          HttpServletResponse response

xml配置

<bean id="paraMethodResolver"  
        class="org.springframework.web.servlet.mvc.multiaction.ParameterMethodNameResolver">  
        <property name="paramName" value="action"/>  
        <property name="defaultMethodName" value="list"/>  
    </bean>  
   	<!-- 页面View层基本信息设定 -->  
    <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver">  
        <property name="viewClass" value="org.springframework.web.servlet.view.JstlView"/>  
		<property name="prefix" value="/WEB-INF/content/"/>
		<property name="suffix" value=".jsp"/>  
    </bean>  
	<!-- servlet映射列表,所有控制层Controller的servlet在这里定义 -->  
    <bean id="urlMapping"  
          class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping">  
        <property name="mappings">  
            <props>  
                <prop key="/admin/index.htm">adminController</prop>
                <prop key="/menu/index.htm">adminController</prop> 
            </props>  
        </property>  
    </bean>
    
	<bean id="adminController" class="com.core.action.AdminController">  
	</bean>  

访问方式类似

http://localhost:8080/BaseS2I/menu/index.htm?action=list

action来自

<property name="paramName" value="action"/>