• HDU-2509 Be the Winner


    http://acm.hdu.edu.cn/showproblem.php?pid=2509

    Be the Winner

    Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1646    Accepted Submission(s): 879

    Problem Description
    Let's consider m apples divided into n groups. Each group contains no more than 100 apples, arranged in a line. You can take any number of consecutive apples at one time. For example "@@@" can be turned into "@@" or "@" or "@ @"(two piles). two people get apples one after another and the one who takes the last is the loser. Fra wants to know in which situations he can win by playing strategies (that is, no matter what action the rival takes, fra will win).
     
    Input
    You will be given several cases. Each test case begins with a single number n (1 <= n <= 100), followed by a line with n numbers, the number of apples in each pile. There is a blank line between cases.
     
    Output
    If a winning strategies can be found, print a single line with "Yes", otherwise print "No".
     
    Sample Input
    2
    2 2
    1
    3
     
    Sample Output
    No
    Yes
     1 #include<iostream>
     2 #include<algorithm>
     3 using namespace std;
     4 int main()
     5 {
     6     int   n,i,a[50];
     7     int temp,ans;
     8     while(~scanf("%d",&n))
     9       {
    10           temp=0;
    11           ans=-1;
    12         for(i=0;i<n;i++)
    13         {
    14             scanf("%d",&a[i]);
    15             if(i==0)
    16                 ans=a[i];
    17             else
    18                 ans=ans^a[i];
    19             if(a[i]>1)
    20                  temp=1;
    21         }
    22         if(temp==0)
    23         {
    24             if(n%2==1)
    25               printf("No
    ");
    26             else
    27               printf("Yes
    ");
    28         }
    29         else
    30         {
    31             if(ans==0)
    32               printf("No
    ");
    33             else
    34               printf("Yes
    ");
    35             
    36         }
    37     }
    38     return 0;
    39 }
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  • 原文地址:https://www.cnblogs.com/cancangood/p/3512825.html
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