• CTF论剑厂MISC(2)


    1.easypdf

    使用chorme打开pdf,ctrl+c发现隐藏字符

     粘贴-->

     注意小写即可

    2.损坏的图片

    图片文件打不开,尝试使用winhex打开看看

     

    而 png的头为 89504E47

    推测可能整个文件颠倒了

    将其颠倒回来

    file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    ans=""
    for i in range(len(file),0,-2):
        tmp=file[i-2:i]
        ans+=tmp
        #print(tmp)
    print(ans)

    ********************************************

    小知识

      • Python中的[::-1]

      • 这个是python的slice notation的特殊用法。
        b = a[i:j] 表示复制a[i]到a[j-1],以生成新的list对象
      • 当i缺省时,默认为0,即 a[:3]相当于 a[0:3]
        当j缺省时,默认为len(alist), 即a[1:]相当于a[1:10]
        当i,j都缺省时,a[:]就相当于完整复制一份a了
      • b = a[i:j:s]这种格式呢,i,j与上面的一样,但s表示步进,缺省为1.
        所以a[i:j:1]相当于a[i:j]
      • 所以a[::-1]相当于 a[-1:-len(a)-1:-1],也就是从最后一个元素到第一个元素复制一遍。

    ********************************************

     将其写入winhex之中,编辑–剪贴板数据–粘贴–ASCII Hex

     

     保存即可成为正常的图片,是一张二维码

    识别即可

     

    3.怀疑人生

     解压之后是三个文件

     第三个最简单

    使用点我的工具即可

     第一个是个加密的zip

    使用winhex,没有发现有价值的信息,使用字典破解试试,结果就破解成功了..

    (自己去网上找些字典,很容易找的)

    解压之后得到一个txt

     最后有等号,推测是base64加密的,解密之

    u66u6cu61u67u7bu68u61u63u6bu65u72

    为16进制的数据,将其转为字符串

    flag{hacker

    看来这个密码是由三部分拼凑而成

    现在来看看第二张图片,按照套路,先放进winhex看看

    粗看没什么,但是仔细看看,发现有玄机:

     估计第二段密码就是在ctf2.txt里面

    但不知道怎么拆开,看了其他大佬的writeup

    ZIP Archive (zip),
    文件头:504B0304   文件尾:50 4B

     之后复制16进制数据并保存,但是提示需要密码

    那怎么办呢?解密呗

    然而并不能破解,后来知道有伪写一说

    伪写介绍

    修改01为00之后

     保存为zip就可以破解了

     破解之后打开txt

    ..... ..... ....! ?!!.? ..... ..... ....? .?!.? ....! .?... ..... .....
    ..!?! !.?.. ..... ..... ..?.? !.?.. ..... ..... ..... ..... !.?.. .....
    ..... .!?!! .?!!! !!!!! !!!!? .?!.? !!!!! !!!!! !!!!! .?... ....! ?!!.?
    !!!!! !?.?! .?!!! !!!!! !!!!! .!!!. ?.... ..... ..... .!?!! .?... .....
    ..... .?.?! .?!.? .

    查资料之后发现,这是ook编码 (花里胡哨的...)

    之后又不知道怎么做了...试了base64也没有用,然后别人告诉我,是base58....

    拼接之后

    flag{hackermisc12580}

    4.向日葵

     打开之后只是一张普通的图片,放进winhex瞧一瞧

     有一个rar,解压之后

    在一个a[5][5]的二维数组中有下列几个元素
    (2,5)
    (5,1)
    (2,4)
    (2,5)
    (3,5)
    (3,2)
    (1,4)
    (5,1)
    (2,2)
    (2,5)
    (4,5)
    (2,1)
    (1,2)
    (4,5)
    (5,5)
    那么flag是什么呢?

    完全没有思路...

    看了别人的思路..才知道

     之后还需要一次凯撒密码

    合理的为 ithinkctfiseasx,但是答案是ithinkctfiseasy。。。(具体我也不知道为啥..)

    这太难想到了............................

    我好菜啊....

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  • 原文地址:https://www.cnblogs.com/caishunzhe/p/13681192.html
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